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Gazlar aralashmasining xossalarini hisoblash usuli


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11.2 Gazlar aralashmasining xossalarini hisoblash usuli


Supersiqilish koeffitsienti Latonov-Gurevich formulasi bilan aniqlanadi:


z=(0,4 lg(T pr )+0,73) Rpr +0,1 R pr ,… (9)

Gazlar aralashmasining psevdokritik harorati:


T PC \ u003d T cr i i (10)


Gazlar aralashmasining psevdokritik bosimi:


R kompyuter = R cr i i (11)


bu erda T cri , P cri - alohida komponentlar uchun kritik harorat va kritik bosim qiymatlari, K, MPa;


i - gazdagi komponentning mol ulushi;
Malumot harorati:

T pr \u003d T / T kompyuter (12)


Past bosim:


R pr \u003d R / R kompyuter (13)


bu yerda T, R – ish harorati va bosimi, K, MPa;


11.3 Shlangi qarshilikni hisoblash


To'xtatilgan quduqning pastki bosimi quyidagi formula bilan aniqlanadi:




,... (1)


,... (2)

Buni quyidagi formula yordamida ham hisoblash mumkin:




,... (3)

(1) va (3) tenglamasidan biz quyidagilarni olamiz:




,... (4)
,... (5)
,... (6)

bu erda d vn - trubaning ichki diametri, mm;




,... (7)

bu erda z cf - gazning o'ta siqilish koeffitsienti;


T cf - quduqdagi o'rtacha harorat, K.
Hisoblash EXCEL da amalga oshiriladi .
Olingan hisob-kitoblar jadvalga kiritiladi:


12. Hisoblash natijalari


12.1 Quduq debisini hisoblash

Jadval.





RO =

0,56


s=

0.0726041


Tsr=

285

TO

e^2s=

1.1562803


Zav=

1


q=

316.15831

t.m3/kun

H=

1082

m


310.73839

t.m3/kun

Din =

8.38E-05

mm


280.41326

t.m3/kun

A=

0.103574



168.97603

t.m3/kun

B=

0,000256


summa =

1076.286


Tayyorgarlik =

7.74

MPa




Pvx=

1

MPa





1.5






3






5.5





B*=

0,00026





teta =

4.17E-06





lambda =

0,02


quduq 362









RO =

0,56


s=

0.0735331


Tsr=

284


e^2s=

1.1584307


Zav=

1


q=

327.76322


H=

1092



323.09418


Din =

8.38E-05



296.82758


A=

0,048363



197.18695


B=

0,000398


summa =

1144.8719


Tayyorgarlik =

7.76





Pvx=

1






1.5






3






5.5





B*=

0,000402





teta =

4.20E-06


quduq 363



RO =

0,56


s=

0.0739372


Tsr=

284


e^2s=

1.1593672


Zav=

1


q=

268.25458


H=

1098



264.82954


Din =

8.38E-05



245.54319


A=

0,01564



171.95469


B=

0,00076


summa =

950.58201


Tayyorgarlik =

7.77





Pvx=

1






1.5






3






5.5





B*=

0,000764





teta =

4.22E-06




12.2 Gazlar aralashmasining xossalarini hisoblash usuli

1. z \u003d (0,4 lg (T cr ) + 0,73) + 0,1 P cr \u003d (0,4 * lg (1,478) + 0,73) + 0,1 * 2,1 \u003d 0,83


2.T pk = T kr i \u003d 0,9848 * 190,5 + 0,00114 * 305,4 + 0,0236 * 125,3 + 0,0016 * 304 \u003d 191,41 K
3. R'pc \u003d R cr / i \u003d 0,9848 * 4,88 + 0,00114 * 5,07 + 0,0236 * 3,53 + 0,0016 * 7,64 \u003d 4,914 MPa
4. T = 283 K
T pr \u003d T / T cr \u003d 283 / 191,41 \u003d 1,478 K
5.P= 10,3 MPa
P pr \u003d P / P cr \ u003d 10,3 / 4,9 \u003d 2,1 MPa

12.1-jadval Gaz tarkibi





12.3 Shlangi qarshilikni hisoblash


Xo'sh 361

P \u003d 6,96 MPa P \u003d 7,04 MPa \u003d 4,29 * 10 =0,0206


6,82 MPa 6,89 MPa 4,24*10 0,0204
6,63 MPa 6,79 MPa 4,23*10 0,0202
6,39 MPa 6,50 MPa 4,02*10 0,0193
6,11 MPa 6,21 MPa 4,19*10 0,0198
6,39 MPa 6,50 MPa 4,02*10 0,0195
Xo'sh 362

P \u003d 6,86 MPa P \u003d 7,91 MPa \u003d 4,12 * 10 =0,0197


6,76 MPa 6,93 MPa 4,15*10 0,0198
6,67 MPa 6,69 MPa 4,08*10 0,0196
6,76 MPa 6,94 MPa 4,17*10 0,0198
6,86 MPa 6,98 MPa 4,38*10 0,0208
6,94 MPa 7,01 MPa 4,14*10 0,0195
Xo'sh 363

P \u003d 6,79 MPa P \u003d 6,95 MPa \u003d 4,00 * 10 =0,0191


6,68 MPa 7,01 MPa 4,16*10 0,0198
6,79 MPa 6,26 MPa 4,26*10 0,0205
6,90 MPa 7,01 MPa 4,11*10 0,0197
6,99 MPa 7,06 MPa 4,23*10 0,0203
7,05 MPa 7,09 MPa 4,19*10 0,0199



quduq 361






































































Q=

728

ming m3/kun




Pzab=

7.55

MPa

Tayyorgarlik =

7,74 MPa




(Ppl^2-Pzab)/Q=

0,1658




853

ming m3/kun







7.45

MPa













0,1265




725

ming m3/kun







7.35

MPa













0,1523




638

ming m3/kun







7.25

MPa













0,1456




583

ming m3/kun







7.16

MPa













0,1737




638

ming m3/kun







7.25

MPa













0,1862





































quduq 362






































































Q=

660

ming m3/kun




Pzab=

7.52

MPa

Tayyorgarlik =

7,76 MPa




(Ppl^2-Pzab)/Q=

0,1658




806

ming m3/kun







7.49

MPa













0,1265




930

ming m3/kun







7.47

MPa













0,1523




804

ming m3/kun







7.49

MPa













0,1456




662

ming m3/kun







7.52

MPa













0,1737




804

ming m3/kun







7.56

MPa













0,1862





































quduq 363






































































Q=

798

ming m3/kun




Pzab=

7.45

MPa

Tayyorgarlik =

7,77 MPa




(Ppl^2-Pzab)/Q=

0,1658




919

ming m3/kun







7.39

MPa













0,1265




797

ming m3/kun







7.45

MPa













0,1523




657

ming m3/kun







7.53

MPa













0,1456




519

ming m3/kun







7.59

MPa













0,1737




657

ming m3/kun







7.65

MPa













0,1862



Xulosa

Yuqoridagi hisob-kitoblardan ko'rinib turibdiki, 363-quduq unumdorligi past, ammo olingan ma'lumotlarga ko'ra, prokladkaning yuqori mahsuldorligini aytish mumkin.


Kon hali o'zlashtirishning ikkinchi bosqichida bo'lganligi sababli, quduqlarni tozalashda qatlamga ta'sir qilish orqali suv oqimini rag'batlantirish orqali quduqlarning mahsuldorligini oshirish mumkin.


ADABIYOTLAR RO'YXATI:



  1. Tabiiy gaz va kondensatni qazib olish, tozalash va tashish. Ma'lumotnoma 2 jildda. 1-jild. Nashr. Ha. Korotaeva, R.D. Margulov - M. Nedra, 1984 yil.

  2. Quduqlarni o'rganish bo'yicha ko'rsatmalar. A.I. Gritsenko, Z.S. Aliev, O.M. Ermilov va boshqalar M. Nauka, 1995 y.

3. Quduqlarni gidrodinamik tadqiq qilish fanidan ma’ruza kursi. Yu.V. Kalinovskiy
4. S.N. Buzinov, I.D. Umrixin "Elastik filtratsiya rejimida suv omborlari va quduqlarni tadqiq qilish" - M.: Nedra, 1964. - 272p.
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