1. Transport masalasining qo`yilishi


Download 0.83 Mb.
bet1/5
Sana11.03.2023
Hajmi0.83 Mb.
#1261824
  1   2   3   4   5
Bog'liq
6eRoMBAMCl4QHoyM7oMM5ZDA46dbkwvbZEhejSef

Axborot texnologiyalari va


.
Mavzu:
FAN: jarayonlarni matematik modellashtirish
Reja:
  • Transport masalasining qo`yilishi.
  • Transport masalasining boshlang`ich yechimini topish.
  • Transport masalasining optimal yechimini topish.

1. Transport masalasining qo`yilishi.


Yuk zaxiralari ๐‘Ž1, ๐‘Ž2, . . . ๐‘Ž๐‘š boโ€™lgan m ta joโ€™natish punkti, yukka boโ€™lgan talab ๐‘1, ๐‘2, . . . ๐‘๐‘› boโ€™lgan n ta qabul punktlari berilgan boโ€™lib, joโ€™natish punktlaridan qabul punktlariga birlik yukni tashish harajatlari ๐‘๐‘–๐‘—, ๐‘– = 1 โ€ฆ ๐‘š; ๐‘— = 1 โ€ฆ , ๐‘› boโ€™lsin. . Bu yerda i- joโ€™natish punkti nomeri, j- qabul punkti nomerini bildiradi. Umumiy yuk tashish xarajatlari quyidagi formula orqali beriladi:
๐‘š ๐‘›
๐‘ง = โˆ‘ โˆ‘ ๐‘๐‘–๐‘—๐‘ฅ๐‘–๐‘—
๐‘–=1 ๐‘—=1
Bu yerda ๐‘ฅ๐‘–๐‘—- i nomerli joโ€™natish punktidan j nomerli qabul
punktiga tashiladigan yuk hajmi. Yuk tashish harajatlarini iloji boricha kamaytirish uchun z funktsiyaning minimumini hisoblaymiz:
โˆ‘๐‘›
๐‘ง = โˆ‘๐‘š
๐‘–=1 ๐‘—=1
๐‘๐‘–๐‘—๐‘ฅ๐‘–๐‘— โ†’ ๐‘š๐‘–๐‘› (1)
Yuqoridagi masala jadval koโ€™rinishida quyidagicha ifodalanadi:

Qabul
punktlari Joโ€™natish punktlari

1

2

โ€ฆ

n

Yuk
zaxiralari

1

x11

c11

x12

c12

โ€ฆ

x1n

c1n

a1

2

x21

c21

x22

c22

โ€ฆ

x2n

c2n

a2

โ€ฆ

โ€ฆ

โ€ฆ

โ€ฆ

โ€ฆ

โ€ฆ

m

xm1

cm1

xm2

cm2

โ€ฆ

xmn

cmn

am

Yukka boโ€™lgan talab

b1

b2

โ€ฆ

bn

Download 0.83 Mb.

Do'stlaringiz bilan baham:
  1   2   3   4   5




Ma'lumotlar bazasi mualliflik huquqi bilan himoyalangan ©fayllar.org 2024
ma'muriyatiga murojaat qiling