60-odd years of moscow mathematical
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Moscow olympiad problems
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(a + c)(b + d) 4 . 16.2.8.2. Somebody wrote 1953 digits on a circle. The 1953-digit number obtained by reading these figures clockwise, beginning at a certain point, is divisible by 27. Prove that if one begins reading the figures at any other place, one gets another 1953-digit number also divisible by 27. 16.2.8.3. On a circle, distinct points A 1 , . . . , A n are chosen. Consider all possible convex polygons all of whose vertices are among A 1 , . . . , A n . These polygons are divided into 2 groups, the first group comprising all polygons with A 1 as a vertex, the second group comprising the remaining polygons. Which group is more numerous? 16.2.8.4. On a plane, n gears are arranged so that the teeth of the first gear mesh with the teeth of the second gear, the teeth of the second gear with those of the third gear, etc., and the teeth of the last gear mesh with those of the first gear. (See Fig. 18.) Can the gears rotate? Figure 18. (Probl. 16.2.8.4) 16.2.8.5. Let n = 100. Solve the system x 1 + 2x 2 + 2x 3 + 2x 4 + 2x 5 + · · · + 2x n = 1, x 1 + 3x 2 + 4x 3 + 4x 4 + 4x 5 + · · · + 4x n = 2, x 1 + 3x 2 + 5x 3 + 6x 4 + 6x 5 + · · · + 6x n = 3, . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . x 1 + 3x 2 + 5x 3 + 7x 4 + 9x 5 + · · · + (2n − 1)x n = n. Grade 9 16.2.9.1. See Problem 16.2.8.2. 16.2.9.2. Given triangle 4A 1 A 2 A 3 and a straight line l outside it. The angles between the lines A 1 A 2 and A 2 A 3 , A 1 A 2 and A 2 A 3 , A 2 A 3 and A 3 A 1 are equal to α 3 , α 1 and α 2 , respectively. The straight lines are drawn through points A 1 , A 2 , A 3 forming with l angles of π − α 1 , π − α 2 , π − α 3 , respectively. All angles are counted in the same direction from l. Prove that these new lines meet at one point. 44 MOSCOW MATHEMATICAL OLYMPIADS 1 – 59 16.2.9.3. Given the equations ax 2 + bx + c = 0 (1) −ax 2 + bx + c = 0 (2) prove that if x 1 and x 2 are some roots of equations (1) and (2), respectively, then there is a root x 3 of the equation a 2 x 2 + bx + c = 0 such that either x 1 ≤ x 3 ≤ x 2 or x 1 Download 1.08 Mb. Do'stlaringiz bilan baham: |
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