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October 2022
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- The basic facts from scattering problem
Introduction.Nonlinear evolution equations are widely used as models to describe complex physical phenomena in various fields of sciences, especially in fluid mechanics, solid- state physics, plasma physics and biology. The Kaup-Boussinesq system was first studied in the paper [1, 2]. In [3], multisoliton solutions were found, and the asymptotic behavior of these solutions was investigated. In papers [4,5], real finite-zone regular solutions of the Kaup-Boussinesq system are studied. In this work, we consider the following Kaup-Boussinesq type system v v 6uu 18u u 6vv 24vuu 6v u2 0, u u 6vu 6v u 30u u2 0, x t xxx x x x under initial condition v(x,t) v0 (x), u(x,t) t 0 u0 (x), x . (2) t 0 The functions v0(x), u0(x) satisfy the following conditions: (i) u0(x) is absolutely continuous on each finite segment , , and the inequalities hold |u0 (x) | dx , (1 | x |)[| v0 (x) | | u0 (x) |]dx , (3) (ii) the operator generated by the differential expression d 2 2 T (0, k) : dx2 v0 (x) 2ku0 (x) k has exactly 2N simple eigenvalues k1(0),k2 (0),...,k2 N (0) . The main aim of this work is to derive representations for the solutions v(x,t) and u(x,t) of the Cauchy problem (1)–(3) within the inverse scattering method for the quadratic pencil of Sturm-Liouville operators: T (t, k) y : y'' v(x,t) y 2ku(x,t) y k 2 y 0, х . (4) The inverse scattering problem for the quadratic pencil of Sturm-Liouville operators in the class of “rapidly decreasing” functions was solved in the works [6,7], with periodical potential in [8,9]. The basic facts from scattering problemIn this section we give basic information about the scattering theory for the Sturm–Liouville equation with an energy-dependent potential. Consider the following quadratic pencil of Sturm-Liouville equatins T (0, k) y : y'' v(x) y 2ku(x) y k 2 y 0, х (5) each finite segment , , and the inequalities hold |u x | dx , (1 | x |)[v(x) | u(x) |]dx . (6) Under condition (6), Eq. (5) has solutions Imk 0 and the asymptotic formulas hold f (x, k ), f (x, k ) regular in the half-plane f (x, k) eikx[1 o(1)], f (x, k) eikx[1 o(1)], x , (7) x . (8) For real k 0 , the pairs f (x, k ), f (x, k ) and f (x, k), f (x, k) (the bar over the function here and below denotes complex conjugation) form two fundamental systems of solutions to equation (5). The following relations hold f (x, k) b(k) f (x, k) a(k) f (x, k) , (9) f (x, k) b (k) f (x, k) a(k) f (x, k). (10) The functions a(k ) and b(k ) are defined for all k R* (, ) \{0} and the following equality is fulfilled a(k ) 1 2ik W f , f, b(k ) 1 2ik W f , f, Moreover, the function a(k ) a(k) 2 b(k) 2 1, k R* . admits an analytic continuation to the half-plane Imk 0 and can have at most a finite number of zeros k1,k2 ,...,kN , besides, at k kn , n 1,2,..., N the following equality holds: n n f (x, k ) B f (x, kn ) , (11) where the quantities B are independent of x . The corresponding functions f (x, kn ) n are the only L2 (R) solutions of (5) for Imk 0 and are the 'bound states'. The set of the quantities r (k) b(k) , k R, k , k ,..., k , , ,..., (12)
a(k) 1 2 N 1 2 N and r (k) b (k) , k R, k , k ,..., k , , ,..., (13) a(k) 1 2 N 1 2 N are called the left and right scattering data of Eq. (5), respectively, here n B n , n k kn 1, 2,..., N . (14) respectively. We now turn to the question of constructing u(x) and v(x) from scattering data. Note that scattering data (12), (13) and F (x) are bijectively related via transforms N 1 F (x) i e iknx r (k)eikxdk . (15) n 2 n1 To restore the coefficient functions u(x) and v(x) in equation (5) from the right reflection coefficient r (k ) we proceed as follows: to K (0) (x, y) L (x,), K(1) (x, y) L (x, ) integral equations 1 1 F (x y) K (0) (x, y) K (0) (x,t)F (t y)dt 0, x x y , iF (x y) K (1) (x, y) K (1) (x, t)F (t y)dt 0, x x y . Next, we have to define the function (x) equation of the Volterra type as a solution to a nonlinear integral in which (x) (t, (t))dt, x x , Φt, z Re K0 t,t m K 1 t,t sin2z 2 Re K 1 t,t sin2z 2 Im K 0 t,t cos2z and we put K x, y K 0 x, y cos x K 1 x, y sin x . u(x) (x) , v(x) u2 (x) 2 d Re K (x, x)cos (x) Im K (x, x)sin (x) . dx It is worthy to remark that the functions 1 hn (x) d [ f dk (x, k) B f n (x, k)] (16) k kn k kn are solutions of the equations T (k ) y k 2 y, n 1, 2,..., N . For Imk 0 , using (7) and n n (8), we obtain the following asymptotics n h (x) eiknx , x , (17) n n h (x) Beiknx , From asymptotics (7), (8), (17) and (18) we get x . (18) W{h (x), f (x,k )} 2ik , W{h (x), f (x, k )} 2ik B n n n n n n n Download 5.08 Mb. Do'stlaringiz bilan baham: |
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