1- masala. Xajmi v1=1 m3 bo’lgan xavoni R1=1 kgs/sm2 bosimdan (absolyut) to R2= 7.5 kgs/sm2 bosimgacha (absolyut) adiabatik siqish jarayonida sarflangan nazariy ishning solishtirma mikdorini aniqlang. Agar xavoning dastlabki xarorati T1=200S bo’lsa, uning qiymati jarayon yakunida qanday kattalikka ega bo‘ladi?
Masalani yechimi. Adiabatik siqish jarayonida bajarilgan ishning solishtirma mikdori quyidagi tenglamadan aniqlanadi:
Lad = k/(k-1) R1v1 [(R2 /R1)(k -1)/k -1] ,
bu yerda k- adiabata ko’rsatgichi, xavo uchun k = 1,4 .
L ad = 1.4/(1.4-1).1.9.81 104 [(7.5/1)(1.4 -1)/1.4 -1]=
= 3.5.9.81.104[(7/5)0.4/1.4 -1] = 343350. (7.50.2857142 -1) = 267246,8 J/m3.
Siqilgan xavoning xarorati
T2 = T1(R2 /R1) ( k-1)/ k = 20*7.5 0.2857142 = 35,56 0S.
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