We have negligible voltage drop along the channel as the voltage range from drain
and source is
small. Due to negligible voltage drop the channel depth is uniform.
Fig: P-MOSFET in linear mode of operation
e) V
GS
< V
T
, V
DS
<< 0
With increase in V
DS
negatively the current increase. The V
GS
is acting perpendicular on
the MOS so its
effect is the same all over the channel. The electric field induced due to V
DS
is varying from drain to
source as V
DS
is increasing negatively and thus the drop from drain to source also increases. This leads
to reduction of depth of channel towards source than at drain.
f) V
DS
<< 0
With
further increase in V
DS
negatively the drop from drain to source increases and the gate channel
potential reduces from drain to source and thus the depth decreases at source.
At some point of V
DS
the depth of channel at source becomes zero, that point is called pinch - off and the
voltage is pinch -
off voltage.
Pinch – off voltage V
DS
= - (V
GS
- v
T
)
This pinch – off affects the rate of increment of I
D
is small as the V
DS
is high
and resistance of the
channel is increasing as channel area decreases.
Do'stlaringiz bilan baham: