Hosilaning iqtisodga tadbiqlari

Egri chiziqqa o‘tkazilgan urinma
Avval egri chiziqqa o‘tkazilgan urunmaning umumiy ta’rifini beramiz. Uzluksiz EMBED Equation.3 egri chiziqda EMBED Equation.3 va EMBED Equation.3 nuqtalarni olamiz (1-rasm).
EMBED Equation.3 va EMBED Equation.3 nuqtalar orqali o‘tuvchi EMBED Equation.3 to‘g‘ri chiziqqa kesuvchi deyiladi.
EMBED Equation.3 nuqta EMBED Equation.3 egri chiziq bo‘ylab siljib, EMBED Equation.3 nuqtaga cheksiz yaqinlashsin. U holda kesuvchi EMBED Equation.3 nuqta atrofida aylangan holda qandaydir EMBED Equation.3 limit holatiga intiladi.
Berilgan EMBED Equation.3 egri chiziqqa berilgan EMBED Equation.3 nuqtada o‘tkazilgan urinma deb, EMBED Equation.3 kesuvchining EMBED Equation.3 nuqta EMBED Equation.3 egri chiziq bo‘ylab siljib EMBED Equation.3 nuqtaga cheksiz yaqinlashgandagi EMBED Equation.3 limit holatiga aytiladi.
Endi EMBED Equation.3 nuqtada vertikal bo‘lmagan urinmaga ega bo‘lgan EMBED Equation.3 uzluksiz egri chiziq grafiini qaraymiz va uning EMBED Equation.3 burchak koeffitsiyentini topamiz, bu yerda EMBED Equation.3 urinmaning EMBED Equation.3 o‘q bilan tashkil qilgan burchagi. Buning uchun EMBED Equation.3 nuqta va grafikning EMBED Equation.3 abssissali EMBED Equation.3 nuqtasi orqali kesuvchi o‘tkazamiz (2-rasm). Kesuvchining EMBED Equation.3 o‘q bilan tashkil qilgan burchagini EMBED Equation.3 bilan belgilaymiz.
2-rasmdan topamiz:
EMBED Equation.3
EMBED Equation.3 da funksiyaning uzluksizligiga asosan EMBED Equation.3 ham nolga intiladi. Shu sababli EMBED Equation.3 nuqta egri chiziq bo‘ylab siljib, EMBED Equation.3 nuqtaga cheksiz yaqinlashadi. Bunda EMBED Equation.3 kesuvchi EMBED Equation.3 nuqta atrofida aylangan holda EMBED Equation.3 urinmaga yaqinlashib boradi, ya’ni EMBED Equation.3 . Bundan EMBED Equation.3 yoki EMBED Equation.3
Shuning uchun urinmaning burchak koeffitsiyenti
EMBED Equation.3 (1)