Ҳисоб тушунтириш хатида қуйдагиларни аниқлаш керак
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- Gorizantal tekislikda
- Tanlangan podshipnik uchun C
- Vallarning xavfsizlik koeffitsienti
- Mustahkamlik zonasi
- Shponka tanlash
Vertikal tekislikda
d ∑MA = 0 RBV N ∑MB = 0 RVA ⋅l + Fr1 ⋅l2 − Fr2 ⋅l1 − Fa1 ⋅ dm2 / 2 = 0 RVA N RVA + RBV − Fr2 − Fr1 = 0 Tekshirish: 4625−1454−910−2261= 0 0 = 0 1-uchastka 0 ≤ x1 ≤ l1 Mx1 = RVA ⋅ x 1 x1 = 0 Mx1 = 0 x1 = 65mm Mx1 = 80Nm 2-uchastka 0 ≤ x2 ≤ l2 x2 = 0 Mx2 d Nm x2 = 96mm Mx2 d Nm Gorizantal tekislikda ∑MA = 0 − RBH l + Ft2 ⋅l1 + Ft1(l +l2) = 0 RBH N ∑MB = 0 RAH l − Ft2 ⋅l1 + Ft1 ⋅l2 = 0 RAH N RAH + RBH − Ft1 − Ft2 = 0 Tekshirish: 13208.5−4461.5−2477−6270 = 0 0 = 0 1-uchastka 0 ≤ x1 ≤ l1 Mx1 x1 = 0 Mx1 = 0 x1 = 65mm Mx1 =−245.4Nm 2-uchastka 0 ≤ x2 ≤ l2 M x2 = −Ft1 ⋅ x 2 x2 = 0 Mx2 = 0 x2 = 96mm Mx2 =−627Nm Umumiy reaksiya kuchi RA = (RAH )2 + (RVA )2 = (−4461.5)2 + (−1454)2 = 4692N RB = (RBГ )2 + (RBV )2 = 13208.52 + 46252 =13994.8N Eng katta eguvchi momentni aniqlaymiz Meg.max = (MV−V )2 + (M Г−Г )2 = (−210)2 + (−627)2 = 661.2Nm Tanlangan podshipnik uchun Cx hisobiy qiymatini aniqlash. №=36210 30.4 radRB =13994.8N ,ω2 = s d = 50 mm C0 = 27 .0kN Cr = 43 .2N Fa1 = 387.5N , RA = 4692N Fa = 387.5 = 0.014 bunda e = 0.19 ga teng. (A1. 4.5.1-jadval) C0 27000 X=0.56, Y=2.30 ga teng. (A1. 4.5.1-jadval) Radial kuchlar ta`sirida hosil bo`lgan bo`ylama kuchlarning qo`shimcha qiymati FSA = 0.83eRrA = 0.83⋅0.19⋅4692 = 740N FSB = 0.83eRrB = 0.83⋅0.19⋅13994 = 2207N Bo`ylama kuchlarning umumlashgan qiymati. ∑ X = 0 − FaA + FaB − Fa = 0 FSA =FSB =2207N qabul qilamiz. Natijada FaA = FaB + Fa = 2207 −387.5 =1819.5N >FSA shart bajarildi. Tayanchlarga ta`sir qiluvchi ekvivalent qiymatini aniqlaymiz. A tayanch uchun Rekv = (XVRrA +YFaA)K1 ⋅K 2 RA =Pr = 4692N Pa =Fa =1271N K1 =1.2 K2 =1.0 l = 0.19 0 FPar = 12712980 = 0.42 > l Pekv = (xVPr + yVPa)K1 ⋅ K 2 = 4692⋅1⋅1.2 = 5448N Podshipnikni ishlash muddatini hisoblaymiz (soat hisobida) Lx = PCekvr 3 = 1195448⋅103 3 =104173 mil. aylanishlar soni Lh soat Vallarning xavfsizlik koeffitsienti Vallarning eng xavfli kesimining xavfsizlik koeffitsientinianiqlashda egilishdagi kuchlanish simmertik holatda burovchi moment pulsatsiyalanuvchi siklda o`zgaradi deb qabul qilingan Val uchun material tanlaymiz Stal 45 Termik ishlovni normalash σB = 570N /mm1 Chidamlilik chegarasi normal kuchlanish δ1 = (0.4÷0.45)δB = 0.43⋅δB = 0.43⋅570 = 246N /mm2 Urinma kuchlanish bo’yicha τ1 = 0.58⋅δ1 = 0.58⋅246 =142N / mm2 Mustahkamlik zonasi S = Sδδ2 ⋅SτSτ = 2 ÷ 2.5 = [τ] S + 2 Normal kuch bo’lsa zona Sδ = Kδ δ−1 Sτ = Kτ τ−1 Eδ⋅δa +ψδ ⋅δm Eτ ⋅τa +ψτ ⋅τm Kδ =1.59 Kτ=1.49 (A1. 4.5.2jadaval) Eδ,Eτ-masshtab koeffisienti Eδ = 0.77 Eτ= 0.67 (A1..4.5.1-jadval) ψδ,ψτ -sezgirlik koeffisienti -jadval) δa =δmax = MWeg.xmax = 517777⋅10.5 3 = 6.55 Wx mm3 τ T 263.09⋅103 Wp =18225 −1335 =16890mm3 Sδ = Kσ δ1 σ ) Shponka tanlash T3 =1563Nm d = 55mm l =40mm t1 = 4.3mm h =10mm b=16mm MPA Foydalanilgan adabiyotlar: Tojiboyev R.N. Shukurov M.M. “Mashina detallarini loyihalash”. Toshkent-1997 Tojiboyev R.N, Jo’rayev A.J “Mashina detallari” 1990 yil Sulaymonov I “Mashina detallari” 1981 yil Dunaev P.F, Lelikov O.R “Detali mashin” 1990 g CHernyavskiy S.A, Bokov K.N, CHernin I.M, Itskovich G.K, 1 ⋅16890 Download 1.15 Mb. Do'stlaringiz bilan baham: |
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