TS — ADEEP алгоритми . O'quv majmuasi uchta vaqt qatoridan iborat bo'lsin - (ularni cyl1, cyl2, су13 belgilaymiz)
Ряд 1 обуч. мн-ва
Ряд 2 обуч. мн-ва
Ряд 3 обуч. мн-ва
Shaklda ko'rsatilgan vaqt ketma -ketligi qatorini anomaliya ekanligini aniqlash kerak. (uni bel deb belgilaymiz).
Подмножество Ij
|
Фактор сглаживания
|
cyl2, cyl3, bel
|
0.370713
|
cyl1, cyl3, bel
|
0.370713
|
cyl3, bel
|
0.0677333
|
cyl1, cyl2, bel
|
0.370713
|
cyl2, bel
|
0.205667
|
cyll, bel
|
0.45465
|
bel
|
0.136392
|
cyl1, cyl2, cyl3
|
0.370713
|
cyl2, cyl3
|
0.362783
|
cyl1, cyl3
|
-0.00448333
|
cyl3
|
-0.128708
|
cyl1, cyl2
|
0.03515
|
cyl2
|
0.0194417
|
cyl1
|
0.0941917
|
- Algoritmga muvofiq, I to'plami ko'rsatilgan to'rtta vaqtli ketma -ketlikdan iborat bo'ladi: I = {cyl1, cyl2, cyl3, bel]. Ij ning barcha mumkin bo'lgan kichik to'plamlari ko'rib chiqiladi (bo'sh to'plam va to'plamdan tashqari). 24-2 = 14 ta shunday kichik to'plamlar mavjud: {{cyl 1}, {cyl 2}, {cyl 3}, {bel}, {cyl 1, cyl 2}, {cyl 1, cyl 3}, {cyl 1, bel}, {cyl 2 , cyl 3}, {cyl 2, bel}, {cyl 3, bel}, {cyl 1, cyl 2, cyl 3}, {cyl 2, cyl 3, bel}, {cyl 1, cyl 3, bel}, {cyl 1, cyl 2, bel}}. Har bir kichik to'plam uchun tekislash koeffitsienti ko'rsatilgan formulalar yordamida hisoblanadi.
- Bu holda, maksimal tekislash koeffitsienti (0,45465) Ix = {cyl1, bel} vaqt qatoridan iborat to'plamga ega, shuning uchun bu istisnolar to'plami. Va vaqt seriyasi istisnolar to'plamiga ({bel} ⊂ IX) kirganligi sababli, bu anomaliya.
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