Men keldimu,dunyo ko`rdimi foyda? Ketsam martabasi osharmi?Qayda!

Ko’paytmaning xususiy xollaridan foydalanib xisoblang.
1) 40∙700∙250 2) 75∙110∙800 3) 500∙320∙600
4) 50∙800∙125 5) 450∙30∙200 6) 2500∙600∙40
7) 80∙60∙1250 8) 130∙500∙200 9) 1250∙450∙400
10) 40∙300∙750 11) 150∙540∙200 12) 160∙250∙120


Taqsimot qonunini qo’llab yeching.
1) 4∙(5-3x) 2) (2-3x) ∙3 3) (3y-5) ∙5
4) 2∙(a+b+c) 5) 3∙ (4+a+b+c) 6) (8+a+b) ∙7
7) 2ab+2ac+2bc 8) 3a-3b 9) m∙8-n∙8

1) a+b+c=101 bo’lsa , (a+b)+(b+c)+(a+c) yig’indini;

2) x+y+z=148 bo’lsa , (2x+y)+(2y+z)+(x+2z) yig’indini hisoblang.


Sonli ifodani qulay usul bilan hisoblang.
1) 7∙55+7∙45+3∙55+3∙45 2) 8∙2+2∙92+8∙98+92∙98
3) 37∙59+41∙37+63∙59+41∙63 4) 356∙73+644∙27+27∙356+73∙64
Natural sonlarni bo'lish.
Berilgan ko'paytma va bitta ko'paytuvchiga ko'ra ikkinchi ko'paytuvchini topish amaliga bo'lish deb ataladi.

0 : а = 0.
Nolni har qanday natural songa bo'lganda yana nol hosil bo'ladi.

1. 
   Noma'lum ko'paytuvchini topish uchun ko'payt­mani ikkinchi ko'paytuvchiga bo'lish kerak.
   

:7

1-misol Tenglikning chap tomonida ko’paytirilib turgan 7
x = 84 : 7 chap tomonga bo’luv bo’lib o’tadi.
x = 12.
1. Noma'lum ko'paytuvchini toping:
a) 18 • x = 450; J:25 | b) 23 • у = 2346; J: 102
Namuna: 30 • x = 23 310,
x = 23 310 : 30,
x = 777.

2. 
   N
   ∙12
   oma'lum bo'linuvchini topish uchun bo'lin-mani bo'luvchiga ko'paytirish kerak
   

2-misol x : 12 = 7

x=84
2.Noma'lum bo'linuvchini toping:
a)x:4 = 207; (J:828) I b)y:5 = 616; (J:3080)
Namuna: x : 44 = 23, x = 44 • 23 = 1012.

3. 
   Noma'lum bo'luvchini topish uchun bo'linuv­chini bo'linmaga bo'lish kerak.
   

3-mosol: 96:x=16
96=16∙x
96:16=x
x=6
3.Noma'lum bo'luvchini toping:
a)360:x = 45; (J:8) || b)861:y = 41 (J:21)
Namuna: 2052 : у = 38, 2052=38∙y, у = 2052 : 38, у = 54.