Namuna test
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NAMUNA TEST
tenglamaning umumiy yechimini toping. y x C
2
x C 2 y x C
y x xC
148.
1 dy x dx
tenglamaning umumiy yechimini toping. 2 2 x y x C 2 2 2 x y x C
2 2 2
y x C
2 2 2 2 x y x C
149. dy xy dx
tenglamaning umumiy yechimini toping. 2 2
y ce
4 2
y ce
2 2
x y ce 2 2 x x y ce 150.
6 dy x dx
tenglamaning umumiy yechimini toping. 2 6 2 x y x C
2 6 2
y x C
2 2 2
y x C
2 2 2 2 x y x C
151. Berilgan tenglamani integrallang: 3 2 1 0 x dx x dy . 2 2 2 ln 1 y x x c
2 2 2 2 ln 1
x x c
2 2 2 2ln 1 y x x c
2 2 2 4ln 1 y x x c
152. Berilgan tenglamani integrallang:
1 3
dx dy . 6 sin 2
1 y x c 6sin 2 1
x c 6 6sin 2
1 y x c 6 7 sin 2
1 y x c 153. Berilgan tenglamani integrallang:
3 2 1 1
dy y y dx
2 2 2
y x c
2 2 y y x c
2 2 y y x c 2
y x c
154. Berilgan tenglamani integrallang:
1 5
dy dx 10 cos 2
1 x y c 10 cos 2 1
y c 10 10 cos 2
1 x y c 10 6 cos 2
1 x y c 155. Berilgan tenglamani 2 2 1 x y c 2 2 1 2 x y c 2 2 2 x y c 2 2 1 x y c integrallang: 2 1 0 y dx xydy
156. Berilgan tenglamani integrallang:
1 .
dx xdy ln
tg cx
2 ln
tg cx
2 ln
tg cx
2 ln y tg cx
157. Berilgan tenglamani integrallang: 2 1 y dx xydy 2 ln 1; 0.
c y x
2 2 ln
1; 0.
c y x
2 ln 1; 0. x c y x
2 2 ln
1; 0.
c y x
158. Berilgan tenglamani integrallang: 2 2 dy xy xy dx 2 1 2; 0. x ce y y
2 1 2; 0. x ce y y
2 1 2; 0. x ce y y
2 1 2; 0.
ce y y
159. Berilgan tenglamani x y a a c
y a a c
x y a a c x y a a c
integrallang: , 0, 1 . x y dy a a a dx
160. Berilgan tenglamani integrallang: 2 1 2 1
. y y e x dy x e dx
2 1 1 .
e c x
2 1 1 .
e c x
2 1 1 .
e c x
2 1 1 .
e c x
161. 4 ta elementdan 2 tadan qilib tuzilgan o’rinlashtirishlar sonini ko’rsating? 12 ta
10 ta 11 ta
13 ta 162. 4 ta elementdan 3 tadan qilib tuzilgan o’rinlashtirishlar sonini ko’rsating? 24 ta
18 ta 20 ta
22 ta 163. 6 ta elementdan 3 tadan qilib tuzilgan 120 ta
110 ta 114 ta
124 ta o’rinlashtirishlar sonini ko’rsating? 164. Bir masalaga ko’rsailgan 9 nomzoddan uch kishi saylanishi kerak.Saylovdagi turli eximollar qancha bo’lishi mumkin? 84 ta
74 ta 94 ta
64 ta 165.AB kesmada C, D, E nuqtalar berilgan.Jami nechta kesma hosil bo’ladi?(bunga AB kesma ham kiradi). 10 ta
14 ta 8 ta
12 ta 166. AB kesmada C, D, E, K, M nuqtalar berilgan.Jami nechta kesma hosil 21 ta
24 ta 20 ta
18 ta bo’ladi?(bunga AB kesma ham kiradi). 167. 1,2,3,4,5,6,7,8,9 raqamlardan nechta 3 xonali nomerlar tuzish mmkin?
729 ta 740 ta
769 ta 719 ta
168. 5 ta har xil dafarni uch bola o’rtasida necha xil usul bilan taqsimlash mmkin. 243 ta
244 ta 242 ta
245 ta 169. To’rt xil bolt va 3 xil gaykadan bittadan olib necha xil juftliklar tuzish mmkin?
12 ta 14 ta
16 ta 10 ta
170. 2 kitob, 3 dafar va 4 qalam bor.Ulardan bittadan 24 ta
18 ta 22 ta
12 ta olinib komplektlar tuzilmoqchi.Bu ishni necha xil usul bilan qilish mmkin. 171. Xodisa extimolining statistik ta’rifini ifodalovchi formulani kursating? W(A)= ( )
M A N
P(A)= m n
P= 2е n
P= е n
172.Ushbu formula kanday formula? P (H:IA)=
1 ( ) ( ) ( ) ( ) n k P Hi P AIHi P Hi P AIHi Baysez
Bernulli Tula extimol Extimol 173.Tasodifiy mikdorning extimol zichligi P(x)= 2 1
) х bulsa, shu tasodifiy F(x)= 1
arctgx+ 1 2 F (x)=-
1 arctgx+ 1 2
F(x)=arctgx+ 1 2 F(x)=
1 arctgx- 1 2
mikdorning taksimot funktsiyasini toping? 174.Yashikda 25 ta shar bor, ulardan 10 tasi ok 15 tasi kora. Yashikdan tavakkal bitta shar olinganda uning ok bulish extimolini toping? 0.4
0.2 0.3
0.5 175.Mukarrar xodisaning extimoli nechaga teng buladi? 1 0.5
0 2 176..Kutida 5 ta ok, 4 ta kizil shar bor. Kutidan kaytarib joyiga kuymasdan, bittalab shar olish tajribasi utkazilayotgan bulsin. 19/81 21/81
20/81 22/81
Birinchi gal ok, ikkinchi gal kizil chikish extimolini toping?
177.n ta boshlang’ich fikriy o’zgaruvchiga ega bo’lgan formulaning chinlik jadvali nechta satrdan iborat buladi 2n ta 2 n ta
3 n ta 4n ta
178.Xodisa extimolining klassik ta’rifini ifodalovchi formulani kursating? P(A)=
P= mesG mesQ
W(A)= ( ) M A N
W(B)= ( ) M A N
179.Xodisa extimolining geometrik ta’rifini ifodalovchi formulani kursating? P =
P(A)= m n
W(A)= ( ) M A N
P(A)= n m
180.Tasodifan 2 honali son tanlandi. Tanlangan son tub son bo’lish ehtimoli topilsin. 7/30
11/30 13/30
3/10 181. 20 dan katta bo’lmagan natural son tasodifan tanlandi. Uni 5 ga karrali bo’lish ehtimoli topilsin. 0,2 0,1
0,3 0,5
182.Ehtimolning klassik ta’rifini aniqlang? Hodisaning ehtimoli deb, hodisaning yuz berishiga qulaylik tug‘diruvchi hodisalar sonining teng imkoniyatli barcha hodisalarning jami soniga nisbatiga aytiladi Hodisaning ehtimoli deb, hodisaning yuz berishiga qulaylik tug‘dirmaydigan hodisalar sonining teng imkoniyatli barcha hodisalarning jami soniga nisbatiga aytiladi Ehtimolning aksiomalarini qanoatlantirmaydigan funksiyaning sonli qiymati mumkin bо‘lgan hodisaning ehtimoli deyiladi Ehtimolning aksiomalarini qanoatlantiruvchi funksiyaning sonli qiymati mumkin bо‘lmagan hodisaning ehtimoli deyiladi
183. Ehtimolning geometrik ta’rifini aniqlang? Nuqtaning D sohada
yotuvchi istalgan 1
sohaga tuPshish ehtimoli deb, 1
soha yuzining D soha
yuziga nisbatiga aytiladi Tajribalar soni
yetarlicha katta bо‘lganda hodisa m
marta yuz bersin. m n nisbatni hodisa ehtimoli deb ataladi Tajriba о‘tkazilayotgan sharoitni о‘zgartirmaganda atrofida hodisaning yuz berish chastotasi tebranadigan va chastotani xarakterlaydigan sonni shu hodisaning ehtimoli deb ataladi Hodisaning ehtimoli deb, hodisaning yuz berishiga qulaylik tug‘diruvchi hodisalar sonining teng imkoniyatli barcha hodisalarning jami soniga nisbatiga aytiladi 184.Elementar hodisa deb, tajribaning har bir ..............siga aytiladi Natijasiga Ulushiga Takrorlanishiga Ulushi va natijasiga 185.Barcha .................lar tо‘plami
elementar hodisalar fazosi deyiladi Elementar hodisalar Tajribalar Sinovlar Sinovlar va elementar hodisalar 186.
ning........hodisa deb ataladi
Ixtiyoriy qism tо‘plami Natijasi Takrorlanishi Ixtiyoriy bo’sh bo’lmagan tо‘plami
187.A va B hodisalarning yig‘indisi A B deb
........elementar hodisalardan iborat bо‘lgan hodisaga aytiladi Yoki A ga yoki B ga, yoki ularning ikkalasiga ham tegishli B ga tegishli Yoki A ga yoki B ga, yoki ularning ikkalasiga ham tegishli bo’lmagan A ga tegishli 188. A va B hodisalarning kо‘paytmasi
deb
........elementar hodisalardan iborat bо‘lgan hodisaga aytiladi A va B larning har ikkalasiga tegishli B ga tegishli A ga tegishli A va B larning yigindisiga tegishli 189. A va B hodisalarning ayirmasi A ga tegishli, lekin B ga tegishli bо‘lmagan B ga tegishli, lekin A ga tegishli bо‘lmagan B ga tegishli bо‘lmagan A ga tegishli
/ A B deb
........elementar hodisalardan iborat bо‘lgan hodisaga aytiladi 190...............muqarrar hodisa deyiladi tо‘plamga Ehtimoli 1 ga teng hodisaga 0
Ehtimoli qiymati 0,5 ga teng hodisa
191 .............mumkin bо‘lmagan hodisa deyiladi 0
tо‘plam Ehtimoli qiymati 1 ga teng hodisa Ehtimoli qiymati 2 ga teng hodisa 192. Agar
bо‘lsa, u holda hodisalar ...........hodisalar deyiladi va
о‘rniga A B yoziladi Birgalikda bо‘lmagan Birgalikda bo’lgan O’zaro bog’liqli bo’lgan Qarama-qarshi 193. Agar ................. bо‘lsa, u holda
o
va A A
A A
A A o ва A A o
A A o
hodisa A ga qarama- qarshi hodisa deyiladi 194.Agar ....................bо‘lsa, u holda 1
, ,.....,
n A A A
hodisalar tо‘la gruppani tashkil etadi deyiladi 1 2
) ва .....
i j n A A o i j A A A
( ) i j A A o i j
1 2 ..... n A A A
( ,
1, , )
j A A o i j n i j 195. Mumkin bо‘lmagan xodisani ehtimoli nimaga teng? 0 1
0,1 196.Muqarar xodisani extimoli nimago teng? 1 0 2 0,6
197.Tasodifiy xodisani extimoli nimago teng? (0;1) 1
0.6 198.Agar A hodisaning har bir rо‘y berishi natijasida B hodisa ham rо‘y bersa, A
B deb yoziladi va “A hodisa B hodisani ergashtiradi” A va B birgalikda A va B birgalikda emas B
deb yoziladi va “A hodisa B hodisani ergashtiradi” u holda .................deb ataladi
199. Agar A hodisa B hodisani ergashtirsa, u holda A ga kirgan har bir
hodis.............bо‘ladi B ga ham tegishli B ga tegishli emas \
ga tegishli \
ga tegishli 200.Agar .............bо‘lsa, A va B lar teng kuchli hodisalar deyiladi
\ A B o
\
A B
201.Quyidagi nisbat ............ga A hodisaning nisbiy chastotasi deyiladi.
- A hodisa rо‘y bergan tajribalar soni, n - tajribalar umumiy soni ( ) m W A n
( ) m P A n
/ A B
( ) n W A m
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