O‘zbekiston respublikasi oliy va o‘rta maxsus ta’lim vazirligi guliston davlat universiteti Ekologiya va geografiya kafedrasi


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Sanoat ekologiyasi

Masalani echilishi:
Q=q·S·G=4,5·1,5·20=135 m3/soat
V=
L1=x1
L2=x2
L1+L2=0,008+0,011=0,019 m.
L=(1,1:1,2)·L=(1,1:1,2)·0,019=0,017 m.


1 - amaliy mashg’ulot variantlari



1-variant

2-variant

3-variant

4-variant

5-variant

S=1,4 m
ω1=1,71 mm/s
ω2=0,60 mm/s
q=4,15 l/s
G=15

S=2,3 m
ω1=1,90 mm/s
ω2=0,79 mm/s
q=3,5 l/s
G=17

S=3,1 m
ω1=1,85 mm/s
ω2=0,53 mm/s
q=4,9 l/s
G=11

S=1,1 m
ω1=1,45 mm/s
ω2=0,42 mm/s
q=4,3 l/s
G=9

S=1,7 m
ω1=1,69 mm/s
ω2=0,87 mm/s
q=3,7 l/s
G=16

6-variant

7-variant

8-variant

9-variant

10-variant

S=1,9 m
ω1=1,63 mm/s
ω2=0,42 mm/s
q=4,22 l/s
G=14

S=2,1 m
ω1=1,70 mm/s
ω2=0,22 mm/s
q=2,5 l/s
G= 12

S=2,55 m
ω1=1,53 mm/s
ω2=0,52 mm/s
q=3,3 l/s
G=8

S=1,3 m
ω1=1,44 mm/s
ω2=0,36 mm/s
q=4,1 l/s
G=13

S=11,5 m
ω1=1,13 mm/s
ω2=0,11 mm/s
q=3,3 l/s
G=18

11-variant

12-variant

13-variant

14-variant

15-variant

S=12,5 m
ω1=1,23 mm/s
ω2=0,22 mm/s
q=2,1 l/s
G=14

S=14,5 m
ω1=1,33 mm/s
ω2=0,33 mm/s
q=3,9 l/s
G=7

S=15,6 m
ω1=1,43 mm/s
ω2=0,54 mm/s
q=2,7 l/s
G=5

S=13,7 m
ω1=1,53 mm/s
ω2=0,47 mm/s
q=3,1 l/s
G=7

S=12,8 m
ω1=1,63 mm/s
ω2=0,62 mm/s
q=4,1 l/s
G=19

16-variant

17-variant

18-variant

19-variant

20-variant

S=7,7 m
ω1=1,52 mm/s
ω2=0,36 mm/s
q=3,1 l/s
G=3

S=11,8 m
ω1=1,43 mm/s
ω2=0,25 mm/s
q=4,9 l/s
G=8

S=12,9 m
ω1=1,21 mm/s
ω2=0,13 mm/s
q=2,7l/s
G=13

S=3,5 m
ω1=1,98 mm/s
ω2=0,35 mm/s
q=5,5 l/s
G=5

S=12 m
ω1=1,93 mm/s
ω2=0,41 mm/s
q=2,5 l/s
G=11

21-variant

22-variant

23-variant

24-variant

25-variant

S=11,5 m
ω1=1,85 mm/s
ω2=0,56 mm/s
q=5,5 l/s
G=12

S=9,5 m
ω1=1,21 mm/s
ω2=0,62 mm/s
q=3,2 l/s
G=7

S=10,5 m
ω1=1,27 mm/s
ω2=0,73 mm/s
q=3,9 l/s
G=9

S=14,5 m
ω1=1,39 mm/s
ω2=0,67 mm/s
q=3,7 l/s
G=14

S=10 m
ω1=1,63 mm/s
ω2=0,93 mm/s
q=2,5 l/s
G=8

26-variant

27-variant

28-variant

29-variant

30-variant

S=9,5 m
ω1=1,43 mm/s
ω2=0,77 mm/s
q=3,7 l/s
G=6

S=13,5 m
ω1=1,23 mm/s
ω2=0,76 mm/s
q=2,9 l/s
G=3

S=15,5 m
ω1=1,93 mm/s
ω2=0,87 mm/s
q=4,9 l/s
G=13

S=8 m
ω1=1,93 mm/s
ω2=0,82 mm/s
q=2,4 l/s
G=15

S=7,5 m
ω1=1,13 mm/s
ω2=0,75 mm/s
q=4,3 l/s
G=17

2 – AMALIY MASHG’ULOT


Sanoat korxonalarining atrof-muhitga ta’sirini baholash


Ishdan maqsad: Sanoat korxonalarining atrof-muhitga ta’sirini baholashni o’rganish.
Korxonalarning atmosferasini umumiy ifloslanishidagi ishtirok etish darajasi bo’yicha sinflash maqsadida quyidagi ko’rsatkichlar kiritiladi:
Zaharli chiqindi moddalar yig’indisi sifatida va kishi boshiga, har bir chiqarib tashlanadigan chiqindilarning xavflilik yoki zaharlilik darajasiga va ifloslantirish manbasiga qarab ularning birlik yuzadan chiqadigan solishtirma miqdori. Bu balans usuli kundalik chiqadigan zararli moddalarning miqdorini aniqlashga, qaralayotgan maydondagi “solishtirma ekologik ta’sirini” va “energiya tejamkorlik” miqdorini o’rganish imkonini beradi.
Masala 2: korxonada xom ashyolarni tayyorlash bo’limida moslamalardan chiqayotgan chang miqdori F=5,0 g/s quvvat va t=25,50C harorat bilan ventilyastion sistema orqali atmosferaga chiqib ketadi. Chiqindilar w=7,5 m/s tezlik bilan, balandligi H=16 m va diametri D=0,6 m bo’lgan quvurdan chiqarib yuboriladi.


V=F·D (1)
H
F=1000·W2·D (2)
H2·T
Havoga chiqadigan chang konstentrastiyasi aniqlash lozim – S chang.
Atmosfera havosiga baho bering.
REM chang=1mg/m3 deb qabul qilinsin.


Hisoblash.
F=5,0 g/s, T=25,50C, W=7,5 m/s, H=16 m, D=0,6 m


Masalani echilishi:
V=FD/H=5·0,6/16=0,19 m
F=1000·W2·D/H2·T=1000·7,52·0,6/162·25,5=33750/6528=5,2 m/s

Olingan natijalar shuni ko’rasatadiki, sanoat korxonalaridan chiqayotgan zaharli moddalar miqdori atmosfera va atrof muhitga ta’siri juda yuqoridir.


Zaharli chiqindi moddalar yig’indisi sifatida va kishi boshiga, har bir chiqarib tashlanadigan chiqindilarning zaharlilik darajasiga va ifloslantirish manbasiga qarab ularning birlik yuzadan chiqadigan solishtirma miqdori aniqlandi. Bu balans usuli kundalik chiqadigan zararli moddalarning miqdori aniqlandi.


2 - amaliy mashg’ulot variantlari

1-variant

2-variant

3-variant

4-variant

5-variant

F=4,0 g/s
T=24,50C
W=6,5 m/s
H=15 m
D=0,5 m

F=7,0 g/s
T=20,50C
W=5,5 m/s
H=14 m
D=0,3 m

F=6,0 g/s
T=22,50C
W=4,5 m/s
H=12 m
D=0,2 m

F=8,0 g/s
T=21,50C
W=7 m/s
H=16 m
D=1,5 m

F=9,0 g/s
T=23,50C
W=6 m/s
H=16 m
D=2,5 m

6-variant

7-variant

8-variant

9-variant

10-variant

F=10,0 g/s
T=200C
W=8,5 m/s
H=16 m
D=1,5 m

F=5,5 g/s
T=19,50C
W=7,5 m/s
H=11 m
D=0,5 m

F=4,5 g/s
T=18,50C
W=8,5 m/s
H=13 m
D=0,8 m

F=3,5 g/s
T=17,50C
W=9,5 m/s
H=17 m
D=0,9 m

F=5,5 g/s
T=15,50C
W=7,5 m/s
H=13,5 m
D=1,2 m

11-variant

12-variant

13-variant

14-variant

15-variant

F=5 g/s
T=24,50C
W=7,5 m/s
H=21 m
D=1,5 m

F=6,0 g/s
T=30,50C
W=7,5 m/s
H=23,5 m
D=1 m

F=11,0 g/s
T=21,50C
W=4,5 m/s
H=13 m
D=0,6 m

F=12,0 g/s
T=27,50C
W=3,5 m/s
H=15 m
D=0,5 m

F13,0 g/s
T=26,50C
W=7,5 m/s
H=17 m
D=0,7 m

16-variant

17-variant

18-variant

19-variant

20-variant

F=5,5 g/s
T=20,50C
W=8 m/s
H=6 m
D=1,7 m

F=6,5 g/s
T=300C
W=11 m/s
H=5 m
D=1,9 m

F=7,5 g/s
T=35,50C
W=13 m/s
H=13 m
D=1,2 m

F=7,0 g/s
T=35,50C
W=6,5 m/s
H=12,5 m
D=1,1 m

F=8,5 g/s
T=33,50C
W=7,5 m/s
H=13,5 m
D=1,6 m

21-variant

22-variant

23-variant

24-variant

25-variant

F=9,5 g/s
T=28,50C
W=8,5 m/s
H=14,6 m
D=1,3 m

F=11,0 g/s
T=15,50C
W=4 m/s
H=12,5 m
D=0,3 m

F=15,0 g/s
T=10,50C
W=6 m/s
H=13 m
D=0,5 m

F=13,0 g/s
T=12,50C
W=9 m/s
H=13 m
D=0,6 m

F=9,5 g/s
T=250C
W=9,5 m/s
H=10 m
D=1,6 m

26-variant

27-variant

28-variant

29-variant

30-variant

F=6,5 g/s
T=240C
W=6,5 m/s
H=12 m
D=1,3 m

F=4,5 g/s
T=270C
W=3,5 m/s
H=15 m
D=1,1 m

F=6,0 g/s
T=27,50C
W=9,5 m/s
H=17 m
D=0,7 m

F=7,0 g/s
T=17,50C
W=11,5 m/s
H=19 m
D=0,9 m

F=8,0 g/s
T=15,50C
W=13,5 m/s
H=21 m
D=0,5 m

3 – AMALIY MASHG’ULOT


Maydalangan qurilish materiallarini aralashtirish vaqtida chiqadigan chang miqdorini hisoblash


Ishdan maqsad: Maydalangan qurilish materiallarini aralashtirish vaqtida chiqadigan chang miqdorini hisoblashni o’rganish.
3 – masala. Omborxonalarda, sochiluvchan maydalangan qurilish materiallarini saqlash joylarida aralashtirish vaqtida chiqadigan chang miqdorini qurilish joylarida quyidagi xarakteristikalari asosida baholash.





Boshlang’ich ma’lumotlar

Materialni nomlashi, maqsadi

Keramzit

1

Sochiladigan joylarda ishlab chiqari quvvati

75

2

Chang zarrachalari miqdori K1

0,08

3

Aerozolga o’tadigan chang miqdori K2

0,06

4

Meteorologik sharoitni (shamol tezligi) hisobga oluvchi koeffistient K3

1,1

5

Sochilish joylarida tashqi ta’sirdan muhofaza qilish darajasini xarakterlovchi koeffistient K4

0,7

6

Materialni namligini hisobga oluvchi koeffistient K5

0,8

7

Materialni yuqoriga ko’tarish balandligini hisobga oluvchi koeffistient K6

1,1

8

Saqlanadigan materialni yuzasini hisobga oluvchi koeffistient K7

1,4

9

1 kv.m yuzadan chiqadigan chang, q g/m2

0,005

10

Saqlanadigan joy yuzasi, F0 m2

100




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