* GULISTON DAVLAT UNIVERSITETI AXBOROTNOMASI,
Tabiiy va qishloq xo‘jaligi fanlari seriyasi. 2021. № 1
23
Because the
, then the first two coefficients
and
of series (21) will be the
same for all cases
. Coefficients
,
,
ряда (21) для случаев
of series (21) for cases n = 1,2,3 are found in the above way.
It turned out that for all equations obtained for the cases n = 1,2,3, the difference between the left
and right sides is negative for
, positive for
. Taking this into account, we have applied
the half division method specifically for the interval
.
Results and their discussion
Applying the method of half division, we solved the equations obtained in the cases n = 1,2,3
with the following set of values of the initial data (characteristics) of problem (1) -
(7).
In this case, the derived constants will take the following values:
where
.
With the above set of input data, the following values of α were obtained depending on
.
n
0
1
2
3
11,7439
12,1411
12,4648
13,5599
It can be seen that the progress of the interface will increase with an increase in the exponent of the
degree of dependence of ε on
.
Conclusion
With a known α, it is easy to calculate
, from a finite segment of series (1.21) and
by
formula (17), and the interface
is determined by formula (11).
Knowing the boundary
, at a certain value of time will allow us to determine a strip near the
reservoir (channels) with a width
, which can be subject to salinization or waterlogging and
take the necessary measures to prevent them.
References
1. Jamuratov K., Umarov X., Xolboev S. Reshenie odnoy zadachi teorii filtratsiy metodom
kvazistatsionarnogo priblijeniya //GulDU axborotnomasi, 2016. №1.- 7-13 b (in Russian).
2. Jamuratov K., Umarov X.R., Kurbanov J.T. K priblijennomu resheniyu odnoy zadachi teorii
filtratsii dlya malyx znacheniy vremeni // Nauchniy almanax, 2021, N 1.- 217 s (in Russian).
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