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VIII. Zanjirli uzatma hissobi.
Katta yulduzcha tishlari sonni aniqlash
Z₂=Z₁*i_zanj=20*3=60
Yuklamaning hissobiy koeffitsiyent
Ke= Кdin*Ka*Km*KӨ*KR*Kreg
Кdin - dinamik zo'riqish koeffitsiyenti
Ka - o ‘qlararo masofa koeffitsiyenti
Km - moylash turini hisobga oluvchi koeffitsiyent
KӨ - zanjirning o g ‘ ish burchagini hisobga oluvchi koeffitsiyent
KR - zanjirning ishlash rejimini hisobga oluvchi koeffitsiyent
Kreg- zanjirning taranglash turini hisobga oluvchi koeffitsiyent
Ke=1*1.4*1*1.25*0.8*1*1.125*1*1.1*1.25=1.2
Bir qatorli zanjirning qadami
t₁=2.8*
p=17
t1=2.8* =8.9
Zanjirning tezligini aniqlash
V=
t= 12.7

V=

Aylantirish kuchi
F_t=
F_t=
F_t=2112N=2.1kN
Sharnerdagi bosim
P=
P= =0.06

(p)=32[1 + 0.001(𝑧1 - 17)]

(p)=32[1 + 0.001(44 - 17)]=32.864
Zanjir zvenolari sonni aniqlash

Lt=2*at+0.5*Z

Bu yerda:

Z=z₁+z₂=44+116=160 a_t=50
L_t=2*50+0.5*160
Zanjirli uzatmaning markazlar aro masofasi
az=0.25*t[𝐿𝑡 - 0.5 ∗ 𝑍 + ]
a_z=0.25*12.7 =1467
Markazdan qochma kuch
F_v=q*v²
F_v=0.75*1.34^2=1.34
Zanjir salqiligidan hosil bo’ladigan kuch

Ff = 9.81*kf*q*az

F_f=9.81*1.15*0.75*1467=11980

Valdagi xisobiy yuklama

Fx= Ft +2*Ff

F_x=2.1+2*11980=23962.1
IX. Reduktor vallarining dastlabki hisobi

Buralishga ruxsat etilgan kuchlanish qiymati [𝜏]=20 MPa bo'lganda yetaklovchi

valning chiqish oxiridagi diametri quyidagi formula bo'yicha aniqlanadi

yetaklovchi val:

d_v1=
d_v1= =25
Aniqlangan qiymat bo’yicha standart qatordan etaklovchi valning diametr
d_v1 26
Val podshipnik o’rni pog’onasining diametri.
dp1dv1(510) mm
d_p1=26+7=33mm
Valning shesternya o’rnatiladigan pog’onasining diametri.
dk dp1(510) mm
d_k=33+7=40
Yetaklanuvchi val.
Yetaklanuvchi valning chiqish oxiridagi diametric
d_v2=
(𝜏)=25 MPa
d_v2= =39
bo’rtik diametri
ddk (510) mm
d43+7=50

X. Reduktor korpusining konstruktiv o'lchamlari.
Bir pog’onali reduktor korpusining asosiy elementlari

=0.025a +1=0.025*160+1=5 0.02a 0.02*+1=4.2
b=1.5 =1.5*5=7.5 b₁=1.5 =1.5*4.2=6.3
m= =(0.85:1) (0.85:1)*5=4.5 m₁==(0.85:1) (0.85:1)*4.2=4
d₁=(0.03:0.036)a +12=(0.03:0.036)*160+12=(4:6.92)=6.5
d₂=(0.7:0.75)d₁=(0.7:0.75)*6.5=(4.55:4.875)=4.7
d₃=(0.5:0.6)d₁=(0.5:0.6)*6.5=(3.25:3.9)=3.5