3. KTP ni tanlash
Hamma obektlarda to’la quvvat topilgandan so’ng umumiy quvvat kataligiga qarab KTp sonni tanlanadi va shahar istemolchilari 2 toifa bo’lgani uchun ularda yuklanish “0.85” dan oshmasligi kerak.
KTP soni
Agar Sn<10000 kva bo’sa 2 ta KTP
10500 kvan<15500 kva 3 ta KTP
16000 kva< Sn bo’lsa 4 ta KTP tanlashimiz zarur
Variant bo’yicha to’la quvvat 5877.5 kva bo’lgani uchun 2ta komplekt trasformator podstasiya tanlaymiz
KTP1 OBEKT 2.3.4.9.11.12.13.15 lar uchun
Sn=3848kva St=3848/0.8=4811 kva
TM-2500/10
Pkz=26 kvt
Pxx=3.6 kvt
Uk=7%
Yuklama koefitsenti
Kz=Sn/n*St
Kz=3848/2*2500=0.77
KTP qurish joyini aniqlash uchun KTP1 istemolchilar markazini aniqlab olamiz
X0 = Σ(Pri ∙ Xi) / ΣPpi
Y0 = Σ(Pri ∙ Yi) / ΣPpi
Bu yerda ΣPpi KTP1 istemolchilarini aktiv quvvatlari yig’indisi
X0=(150*2.6+304.1*6+304.1*9+8.7*357.6+70*6+6*9.5+330*15.5+ 1605*2.7)/(3126)=3.1 sm
Y0=(150*0.8+304.1*4.9+304.1*4.9+357.6*8.05+70*0.8+6*0.8+285*3.9+ 1605*9.1)/(3126) =5.3 sm
KTP2 OBEKT 1.5.6.7.8.10.14 lar uchun
Sn=2029.5kva St=2029/0.8=2536 kva
TM-1600/10
Pkz=17 kvt
Pxx=2.6 kvt
Uk=6%
Yuklama koefitsenti
Kz=Sn/n*St
Kz=2029/2*1600=0.65
KTP qurish joyini aniqlash uchun KTP2 istemolchilar markazini aniqlab olamiz
X0 = Σ(Pri ∙ Xi) / ΣPpi
Y0 = Σ(Pri ∙ Yi) / ΣPpi
Bu yerda ΣPpi KTP1 istemolchilarini aktiv quvvatlari yig’indisi
X0=(150*14.5+304.1*11.9+210*9+210*11.9+210*15.4+ 357.6*12+330*15.5)/(1130.5)=12.3 sm
Y0=(+150*0.8+304.1*4.9+210*11.05+210*11.05+
11.05*210+357.6*8.05+330*5.7)/(1130.5) =8.2 sm
15500>10000>
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