Effect of pneumotransport pipe length on static and dynamic pressure


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Proceedings of International Scientific Conference on Multidisciplinary Studies 
Hosted online from Moscow, Russia 
Date: 11
th
March, 2023 
ISSN: 2835-5733 Website: econferenceseries.com
9 | 
P a g e
 
EFFECT OF PNEUMOTRANSPORT PIPE LENGTH ON STATIC AND 
DYNAMIC PRESSURE 
Kholboev Doniyor Juraboevich
Namangan Institute of Engineering and Technology, Namangan, 
Uzbekistan Senior teacher of the "Energy" department, 
xolbayev_doniyor@mail.ru tel.+99893-407-37-26 
 
Abstract:
The article reflects the results of the research of the change of air speed and 
aerodynamic force on the cross-section of the pipe during the transportation of cotton 
by pneumatic transport. It contains conclusions and suggestions on effective 
management of cotton pneumatic transport process. 
Keywords: cotton raw material, pneumatic transport equipment, air speed, pipe, 
pipe cross-section, diameter, aerodynamic force. 
 
The process of transporting cotton by air takes place in a closed system isolated from 
the outside atmosphere. In order to visualize this process, we will take the simplest 
scheme of an aerodynamic device and first consider the laws of air movement in it . 
In the picture, 1- suction pipe, 2- fan (pump), 3- drive pipe. 
The fan or pump is located in the center of the pneumatic equipment. When the 
system is at rest, that is, when the fan is not running, it is under the pressure of 
outside atmospheric air. In this case, the dynamic pressure is zero and the pressure 
inside the pipe is equal to the external atmospheric pressure: 
Р
d
=0 , P
tot
= Р
st
= Р
atm
, (1) 
When the fan is activated, it draws air from the first half of the device and blows it 
to the other side. As a result, there is a vacuum environment (thin air) on one side of 
the equipment and a dense air environment (excess pressure) on the other side.
The total air pressure P
tot
that the fan can produce is equal to the sum of the static P
st
and dynamic P
dyn
pressures in the pipe: 

tot
= P 
st
+P
dyn
, (2) 



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