Ismi, Familiyasi sana 5-sinf

Sinf

Ismi, Familiyasi sana 5-sinf Matematikadan 2-BSB savollari

1- variant

1. 
   M5.SA.8 Ko‘paytmani hisoblang:
   

a) 801∙ 15 = (2 ball)

b) 91∙ 12= (2 ball)

2. M5.SA.8 Ko‘paytma ko‘rinishida yozing va hisoblang:

a) 72+72+72+72+72= (2 ball)

b) b+b+b+b+b+b= (1 ball)

3. M5.SA.9 Bo‘lishni burchak usulidan foydalanib bajaring:

a) 11704 : 77= (3 ball)
b) 30653 : 203 = (3 ball)

4. M5.SA.10 Tenglamani	yeching:
a) 𝑥 ∗ 33 = 1386 b) 133: 𝑥 = 19 d) 𝑥: 25 = 25		(3 ball) (3 ball) (3 ball)

5 . M5.SA.20 Masalani yeching:

Bog‘chaga mashinada 250 litr sut keltirildi. Sutni quyib olish uchun sig‘imi 30 litr bo‘lgan bidonlardan nechta kerak ? Oxirgi bidonga qancha sut quyiladi ?
(3 ball)

O‘quvchining to‘plagan balli:

Tekshiruvchi o‘qituvchi: (imzo)

Baholash mezoni

№	Ball	Javob	Deskriptor
1	4	a) 12015 b) 1092	Ko‘paytmalarni hisoblay olib, to‘g‘ri javobga erishsa 2 ball, bitta kamchilik bo‘lsa, 1 ball Ko‘paytmalarni hisoblay olib, to‘g‘ri javobga erishsa 2 ball, bitta kamchilik bo‘lsa, 1 ball
2	3	a) 360 b) 6b	Ko‘paytma ko‘rinishiga keltirsa 1 ball, uni xisoblay olsa, 2 ball Ko‘paytma ko‘rinishiga keltirsa 1 ball
3	6	a) 152 b) 151	Bo‘lishni burchak usulidan foydalanib bajara olsa 3 ball, ozgina kamchiligi bo‘lsa, 2 ball, faqat javobni o ‘zini yozsa, 1 ball Bo‘lishni burchak usulidan foydalanib bajara olsa 3 ball, ozgina kamchiligi bo‘lsa, 2 ball, faqat javobni o ‘zini yozsa, 1 ball
4	9	x=42 x=7 d)x=625	Noma’lum ko‘paytuvchini topa olsa 3ball Noma’lum bo‘luvchini topa olsa 3ball d) Noma’lum bo‘linuvchini topa olsa 3ball
5	3	8 ta bidon kerak 10 litr oxirgi bidonga	Masala yechishda 250ni 30 ga bo‘lib, to‘liqsiz bo‘linmani topa olsa, 1 ball, qoldiqlini topib bo‘lish amalini to‘g‘ri bajarsa, 2 ball, Qoldiqni bilib, qolgan sutga ham bitta idish kerakligini bilsa, 3ball
Jami:	25

Sinf

Ismi, Familiyasi sana

5-sinf Matematikadan 2-BSB savollari

2- variant

1. 
   M5.SA.8 Ko‘paytmani hisoblang:
   

c) 331∙ 15 = (2 ball)

d) 21∙ 36= (2 ball)

2. M5.SA.8 Ko‘paytma ko‘rinishida yozing va hisoblang:

c) 56+56+56+56+56= (2 ball)

d) с + с + с + с + с + с= (1 ball)

3. M5.SA.9 Bo‘lishni burchak usulidan foydalanib bajaring:

a) 7728 : 138= (3 ball)
b) 25760 : 230 = (3 ball)

5 . M5.SA.20 Masalani yeching:

Bog‘chaga mashinada 265 litr sut keltirildi. Sutni quyib olish uchun sig‘imi 30 litr bo‘lgan bidonlardan nechta kerak ? Oxirgi bidonga qancha sut quyiladi ?
(3 ball)

O‘quvchining to‘plagan balli:

Tekshiruvchi o‘qituvchi: (imzo)

Baholash mezoni

№	Ball	Javob	Deskriptor
1	4	a) 4965 b)756	Ko‘paytmalarni hisoblay olib, to‘g‘ri javobga erishsa 2 ball, bitta kamchilik bo‘lsa, 1 ball Ko‘paytmalarni hisoblay olib, to‘g‘ri javobga erishsa 2 ball, bitta kamchilik bo‘lsa, 1 ball
2	3	a)280 b)6c	Ko‘paytma ko‘rinishiga keltirsa 1 ball, uni xisoblay olsa, 2 ball Ko‘paytma ko‘rinishiga keltirsa 1 ball
3	6	a)56 b)112	Bo‘lishni burchak usulidan foydalanib bajara olsa 3 ball, ozgina kamchiligi bo‘lsa, 2 ball, faqat javobni o ‘zini yozsa, 1 ball Bo‘lishni burchak usulidan foydalanib bajara olsa 3 ball, ozgina kamchiligi bo‘lsa, 2 ball, faqat javobni o ‘zini yozsa, 1 ball
4	9	x=45 x=17 d)x=275	Noma’lum ko‘paytuvchini topa olsa 3ball Noma’lum bo‘luvchini topa olsa 3ball d) Noma’lum bo‘linuvchini topa olsa 3ball
5	3	8 ta bidon kerak 25 litr oxirgi bidonga	Masala yechishda 265 ni 30 ga bo‘lib, to‘liqsiz bo‘linmani topa olsa, 1 ball, qoldiqlini topib bo‘lish amalini to‘g‘ri bajarsa, 2 ball, Qoldiqni bilib, qolgan sutga ham bitta idish kerakligini bilsa, 3ball
Jami:	25