Berilgan: K=125 N/m t=8s N=5 m=? Yechilishi

Javob: A) o'zgarmaydi.
28.3. Matematik mayatnik uzunligi 4 marta orttirilsa, uning tebranishlar davri qanday o'zgaradi? A) 4 marta kamayadi B) 2 marta ortadi C) 2 marta kamayadi D) 4 marta ortadi
Berilgan:
𝑙₁ = 4𝑙₁ Yechilishi:Matematik mayatnikning tebranish davrini topish formulasidan
𝑇¹ f =? oydalanimiz:
𝑇2
𝑇₁ = 2𝜋 , 𝑇 ².
Tenglamalar nisbatini olamiz:

𝑇1
, 𝑇2 = 2𝑇1
𝑇₂
Javob: B) 2 marta ortadi.
28.4. Matematik mayatnikning uzuntigi 2,5 m, unga osilgan sharchaningmassi 100 g.Tebranish davri qandey?
A) 3.14 B) 6,28 C) 62.8 D) 31.4
Berilgan:
l=2.5 m Yechilishi: Matematik mayatnikning tebranish davrini topish formulasidan
m = 100 g foydalanamiz:
T=? 𝑇 𝑠
Javob: A) 3,14.
28.5. Matematik mayatnikning uzunligi 4 marta ortganda, uning tebranishlar chastotasi qanday o'zgaradi?
A) 4 marta kamayadi B) 2 marta ortadi C) 4 marta ortadi D) 2 marta kamayadi
Berilgan:
𝑙₁ = 4𝑙₁ Yechilishi: Matematik mayatnikning tebranish chastotasini topish

𝜈1
=? formulasidan foydalanam:
𝜈2
𝜈
Tenglamalar nisbatini olamiz:
𝜈
Javob: D) 2 marta kamayadi.
28.6. Matematik mavatnikning yerdagi tebranish davri T ga teng bo' lsa, erkin tushish tezlanishg yerdagidan n marta katta bo’lgan planetadagi tebranish davri qanday bo' ladi?
𝑇
A) B)√𝑛𝑇 C) 𝑇 D)𝑛𝑇
Berilgan:
𝑇_𝑦𝑒𝑟 = 𝑇 Yechilishi: Matematik mayatnikning tebranish davrini topish 𝑔_𝑠 = 𝑛𝑔_𝑦𝑒𝑟 formulasidan foydalanamiz
𝑇_𝑠 =?
𝑇_𝑦𝑒𝑟 = 2𝜋
Tenglama nisbatini olamiz.
= 𝑠 = 𝑛𝑔𝑦𝑒𝑟 , 𝑇 𝑇 𝑇
^𝑇𝑠 2𝜋√ ^𝑔{𝑦𝑒𝑟
𝑔𝑠
𝑇