Berilgan: K=125 N/m t=8s N=5 m=? Yechilishi

Javob: D)0,628
27-Garmonik tebranishlar tenglamasi
27.1 x=20 A cos15t tenglama asosida garmonik tebranma harakat qiluvchi jisimning tebranishlar amplitudasi qandey?
A)cos15 B)15 C) 20A D) 20
Berilgan: Yechilishi:Garmonik tebranish tenglamasi x=Acos15t
𝑥_𝑚 =?

𝑥 = 𝑥_𝑚 cos(𝜔𝑡 + 𝜑_𝛽) ga  𝑥 = 20𝐴 cos 1 5𝑡 𝑛𝑖 solishti-
rib, quydagini olamiz. 𝑥_𝑚 = 20𝐴.
Javob: C) 20 A
𝑡
27.2 Moddiy nuqta tebranishlari  𝑥 = 2 + 3 sin (4𝜋𝑡 + ) (𝑚) tenglama bilan tavsiflanadi.
4
Nuqtaning eng chetki ikki vaziyatlari orasidagi masofa qanday?
A)8 B)6 C)5 D)4
Berilgan:
𝜋
𝑥 = 2 + 3 sin (4𝜋𝑡 + ) Yechilishi:Nuqtaning eng chetki ikki vaziyatlari 4
S=? orasidagi masofa 𝑆 = 2𝑥_𝑚 = 2 ⋅ 3 = 6𝑚 ga teng bo’ladi:
𝑆 = 2𝑥_𝑚 = 2 ⋅ 3 = 6 𝑚
Javob:B) 6.
𝜋
27.3 Mexanik tebranishlar 𝑥 = 0.3 cos (16𝜋𝑡 + ) qonuniyat bo’yicha ro’y beradi.Tebranishlar
2
davrini toping.
A)1/16 B)1/8 C)8 D)16
𝜋
𝑥 = 0.3 cos (16𝜋𝑡 + ) 2
2𝜋
T=? Yechilishi:Τ = formuladan foydalanamib. Beril-
𝜔
gan tenglamaga asosan 𝜔 = 16𝜋 𝑔𝑎 𝑡𝑒𝑛𝑔
2𝜋 2𝜋 1
𝑇 = = = 𝑠
𝜔 16𝜋 8
Javob: B) 1/8.
27.4. Garmonik tebranayotgan jismning harakat tenglamasi 𝑥 = 0.5 cos 1 0𝜋𝑡 .Jism tebranishlarining chastotasi qanday?
A) 10 B) 50 C) 0,5 D)
Berilgan:
𝑥 = 0.5 cos 1 0𝜋𝑡
𝜈 =?
Yechilishi: Chastotaning siklik chastotaga bog 'lanish formulasidan foydalanamiz:
𝜔 = 2𝜋𝜈;
𝜔
𝜈 =;
2𝜋 Berilgan tenglamaga asosan 𝜔 = 10𝜋 ga teng.
𝜔 10𝜋
𝜈 = = = 5𝐻𝑧

2𝜋 2𝜋