π₯ π₯π Yechilishi: Tebranish tenglamasini yozamiz:
π =? π₯ = π₯π cos(ππ‘ + π0) = π₯ππππ π
Tenglamaga berilgan kattaliklarni go'yamiz:
2 π₯π = π₯ππππ π
π
πππ π ; π = Β± Β± ππ
4
π
Javob: A) Β± Β± ππ
4
4
27.15. Tebranayotgan jismning muvozanat vaziyatidan siljish davrining qanday qismida amplitudaning yarmiga teng bo ladi?
A) 7/12
Berilgan:
|
B) T/3 C) T/4 D) T/8
|
π₯
π₯ = π
2
|
Yechilishi: Tebranish muvozanat vaziyati dan boshlangani uchun tenglama
|
t=?
|
sinus qonuniga bo'ysunadi:
|
π₯π
π₯ = π₯ππ ππππ‘; 2 = π₯ππ ππππ‘;
π 1 π ππππ‘ = ; sin =
6 2
17.16. Garmonik tebranayotgan jism muvozanat vaziyatidan chetki vaziyatgacha boβlgan masalaning birinchi yarmini davrining qanday qismidan oβtadi?
xm
A) T/12 B)T/3 C)T/4 D)T/6
Berilgan:
π₯π
π₯ = Yechilishi: Tebranish muvozanat vaziyatidan boshlangani uchun tenglama sinus 2
t=? gonuniga bo'vsunadi.
π₯π
π₯ = π₯ππ ππππ‘; = π₯ππ ππππ‘;
2
π π 2π π = ππ‘; = π‘; π‘ =
6 6 π 12
Javob: A) T/12.
27.17. Mayatnikning tebranishlar davri 6 s. U muvozanat vaziyatidan eng chetki vaziyatgacha bo'- lgan yo'Ining birinchi yarmini necha sekundda o'tadi?
A) 1,5 B) 1 C) 0,5 D) 0,75
Do'stlaringiz bilan baham: |