Berilgan: K=125 N/m t=8s N=5 m=? Yechilishi


Berilgan: 4 4 ???? ???????? Yechilishi


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Berilgan:

4

4

π‘₯ π‘₯π‘š Yechilishi: Tebranish tenglamasini yozamiz:
πœ‘ =? π‘₯ = π‘₯π‘š cos(πœ‘π‘‘ + πœ‘0) = π‘₯π‘šπ‘π‘œπ‘ πœ‘
Tenglamaga berilgan kattaliklarni go'yamiz:

2 π‘₯π‘š = π‘₯π‘šπ‘π‘œπ‘ πœ‘
πœ‹
π‘π‘œπ‘ πœ‘ ; πœ‘ = Β± Β± πœ‹π‘›
4
πœ‹
Javob: A) Β± Β± πœ‹π‘›
4
4
27.15. Tebranayotgan jismning muvozanat vaziyatidan siljish davrining qanday qismida amplitudaning yarmiga teng bo ladi?

A) 7/12
Berilgan:

B) T/3 C) T/4 D) T/8

π‘₯
π‘₯ = π‘š
2

Yechilishi: Tebranish muvozanat vaziyati dan boshlangani uchun tenglama

t=?

sinus qonuniga bo'ysunadi:

π‘₯π‘š
π‘₯ = π‘₯π‘šπ‘ π‘–π‘›πœ”π‘‘; 2 = π‘₯π‘šπ‘ π‘–π‘›πœ”π‘‘;
πœ‹ 1 π‘ π‘–π‘›πœ”π‘‘ = ; sin =
6 2
17.16. Garmonik tebranayotgan jism muvozanat vaziyatidan chetki vaziyatgacha bo’lgan masalaning birinchi yarmini davrining qanday qismidan o’tadi?
xm
A) T/12 B)T/3 C)T/4 D)T/6
Berilgan:
π‘₯π‘š
π‘₯ = Yechilishi: Tebranish muvozanat vaziyatidan boshlangani uchun tenglama sinus 2
t=? gonuniga bo'vsunadi.
π‘₯π‘š
π‘₯ = π‘₯π‘šπ‘ π‘–π‘›πœ”π‘‘; = π‘₯π‘šπ‘ π‘–π‘›πœ”π‘‘;
2

πœ‹ πœ‹ 2πœ‹ 𝑇 = πœ”π‘‘; = 𝑑; 𝑑 =
6 6 𝑇 12
Javob: A) T/12.
27.17. Mayatnikning tebranishlar davri 6 s. U muvozanat vaziyatidan eng chetki vaziyatgacha bo'- lgan yo'Ining birinchi yarmini necha sekundda o'tadi?
A) 1,5 B) 1 C) 0,5 D) 0,75

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