79-ma’ruza. Mavzu: Ehtimolliklar nazariyasining asosiy tushunchalari Reja


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79, 80-ma’ruza102-126


P(B2)=P(A2)=P()P(A2)P()=q1p2q3= p2q1q3,

P(B3)= P(A3)=P()P()P(A3)= q1q2 p3=p3q2q,

ga ega bo’lamiz.



Bu ehtimolliklarni (80.5) ga qo’yib, izlanayotgan ehtimollikni, ya’ni A1, A2, A3 hodisalardan faqat bittasining ro’y berish ehtimolligini topamiz:

P(B1+B2+B3)= p1q2q3 +p2q1q3 +p3q2q1.

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