O’zbekiston respublikasi oliy va o’rta maxsus ta’lim vazirligi toshkent kimyo texnalogiya instuti shahrisabz filiali texnik mexanik fanidan

4.Shesternya va tishli g’ildirak sonini aniqlaymiz. Cos =0.98
=140
= ; .
Shunda,
Qiya tishli g`ildirakni o`lchamlarini aniqlash.

^1) b = 6^∙^mn ^= 6^∙^2.5=15

^2) da ^= mn^∙^(Z2^+2) = 2.5^∙(110+2)=280

^3) h = 2.25^∙^mn^=2.25^∙^2.5=5.625

^4)^δ0^=3∙mn^=3∙2.5=7.5

^5)^D0^=da ^– 2(h+ δ0^)=280–2(5.625+7.5)=253.7

^6)^lcm^=1.1∙b=1.1∙15=16.5

^7) db^=0.2^∙^da ^= 0.2^∙^280=56

^8) dcm ^= 1.6^∙^db^=1.6^∙56^=89.6

^9)^D1^=^0^.^5^∙^(^D0^+^dcm^)^=^0^.^5^∙^(^253.7^+^89.6^)^=^171.65

10) c=0.2∙b = 0.2∙15= 3.0 11) ha=^mn=2.5 ^12) hf=1.25^∙^mn=1.25^∙^2.5=3.125 ^13)d=mn^∙^Z2=2.5^∙110=275 ^14)df=268.75 ^15)dom=41.025 ^16)dob=301.25

5.Shesternya va tishli g’ildiraklarning asosiy o’lchamlari.
Bo’luvchi diametrlari.
= z₁*m_n/Cos 92 mm
z₂ mm
Tekshiruv:
a_w= a_w= a_w=214 a_w=200 mm,
6.kontakt kuchlanish.
K_Ha=1.3
K_Hβ=1.01
K_Hv=1.05
K_H=K_Ha*K_Hβ*K_Hv=1.3*1.01*1.05=1.37
tishli g’ildirak eni
= a_w
v= v=33.7 v=1.55 da
qiya tishli g’ildiraklar aniqlik darajasini 9 deb qabul qilamiz
7.Kontakt kuchlanishni quydagi formula bo’yicha tekshiramiz.
𝜎𝐻 = 270/a_w* ³/b₂*i_red²=64.5
64.5<427 MPa
8.Tishli ilashmaga ta’sir etuvchi kuchlar
Aylana kuch:
2
Radial kuch:α
tg 0.36, /cos
Normal kuchni topish
F_n=F_t/cosα * cos =1.4/0.97*0.98=1.48N
9.Tishlarni egilishdagi kuchlanish bo’yicha musahkmlikka tekshiramiz.


K_F=K_Fα*K_Fβ*K_Fv eguvchi kuchlanish bo`yicha yuklanish koeffitsienti
K<sub>Fα</sub>=1.0
K<sub>Fβ</sub>=1.01
K<sub>Fv</sub>=1.13
K<sub>F</sub>=1.0*1.01*1.13=1.14
Y<sub>β</sub>=1-β/140=0.9
Y<sub>F</sub>=3.75
𝜎𝐹2 = 1.3*1.14*3.75*0.9/45*3=0.037
3.3 Tasmali uzatmaning hisobi
Hisoblash uchun dstlabki malumotlar: yetaklovchi shikivning aylanishlar soni zatish nisbati ; sirpanish koefitsienti =0.047
D<sub>1</sub>=6* <sub>1</sub>=25.12
GOST 17383-73 Bo`yicha D₁ni 40deb qabul qilamiz.
D₂=D₁*i_tas*(1-0.032)=66.5
i=D₂/D₁*(1-0.032)=4.99=5
i=i_tas-i/i=3-3.25/3.25*100%=-0.82
O’qlararo masofa a=2*(D₁+D₂₎=184
Kichik shikivning qamrov burchagi a^o=180-60*d₂-d₁/a=180-60*263-97/312=64
Tasmaning uzunligi.
_{L=2a+0.5* D1+D2)+(D2-D1)2/4a=887}
Tasmaning uzunligini GOST1284-80dan L=900
Tasmaning tezligi ; v= ₁n₁/60=3.14*97*968/60=4.9 v=4.9deb qabul qilamiz.
Aylana kuch F_t=P₁/v=6.48*10³/4.9=1.3 1.3*10³=1350
Qamrov burchak koefitsienti C_a=1-0.003(180-a^o)=0.6
Tasma tezligi tasirini hisobga oluvchi koeffitsient C_V=1.04-0.0004*V²=1
C_P=1 ,C_O=1,p_o=3
(p)=p_o*C_a*C_v*C_p*C_o=1.8
Tasmaning eni B_tas=F_tas/z*(p)=1350/3*2.7=250 standartdan B_tas=250deb olamiz
Z=3deb olamiz
Tasmaning dastlabki tarangligi F₀= ₀B_tas 1.8*250*5=2250 2250*10^-3=2.25
Tasma tarmoqlarudagi kuchlar yetaklovchinikida F_tas1=F₀+0.5*F_tas=2250+0.5*953=677
Yetaklanuvchi F_tas2=F₀-0.5*F_tas=1575
1=F_tas1/B_tas =2925/250*5=2.34

3.4.Reduktor vallarning dastlabki hisobi.

Kamaytirilgan ruxsat etilgan kuchlanish bo`yich buralishga dastlabki hisobni
o`tkazamiz.Bunda vallarning shestirnya, tishli g`ildirak va podshipnik osti diametrlarini aniqlab eskizini chizamiz.

1. 
   Burulishga ruhsat etilgan kuchlanish qiymati [ bo`lgandagi
   

Yetaklovchi valning chiqish ohridagi diametri quydagi formula bo`yicha aniqlanadi
= =29.8=30 mm

Val diametrini quydagicha qabul qilamiz =30 mm

2.Podshipnik osti bo`ynining deyametri =40mm shesternya val bilan birgalikda
tayyorlanadi.
3.valning shesternaga o`rnatiladigan pog`onasining diametri d_k1=50



Yetaklovchi valning eskiz chizmasi

3.Yetaklanuvchi valning chiqish oxirdagi diametrni aniqlaymiz (λ)=25 MPa. deb qabul

qilamiz

= = =42.6=44 mm

Val diametrni quydagicha qabul qilamiz: = 44 mm

Podshipnik osti bo’ynining diametrni mm
tishli g’ildirak osti diametrni =60 mm deb qabul qilamiz.
Bo’rtiq diametrni mm deb qabul qilamiz.
Val oxirining uzunligi l₁=(1.5……2)*d_v1=2*30=60 l₂=(1.5…2)*d_v2 =2*44=88
l_k=l_ct=(1.2…1.5)*d_k1=1.5*50=75 l_k=l_ct=(1.2…1.5)*d_k2=1.5*60=90

Yetaklanuvchi valning eskiz chizmasi

3.5.Shesternya va tishli g’ildirakning konstruktiv o’lchamlari.

Shesternya:

mm,
Tishli g’ildirak:
mm, mm.
Tishli g’ildirak gupchagining diametric va uzunligi .
mm.
mm
deb qabul qilamiz.
Tishli g’ildirak bo’g’inining qalinligi.

mm deb qabul qilamiz.
Disk qalinligi C=0.3 C=0.3 C=12 mm.