R. X. Maksudov
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R. X. Maksudov
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- } - c a -c L - c u/ c p kVt bunda: Ca = 0.91; CL = L/L0=518/1600 = 0.32 boTganda CL
- В - ( Z - \)t + 2 f
- Fc = 7 5 0 j £ T + Z - q v - H, bunda: f, -u za tila y o tg a n quvvat, kVt; Cp, C a-qiymatlari yuqorida berilgan; V
—Г2 • 944 -
3. 14(170 + 90) + J[2 ■ 944 - 3 . 14(170 + 9 0)]3 - 8(170 - 9 0 )2 = 2 6 4 8 L v) E nsiz ponasim on tasm alar u zatm alar uchun a = ^ [2 • 518 - 3.14(120 + 63) + +V'[2- 5 1 8 —3.14(120 + 63 )] 2 - 8 ( 1 2 0 - 63) 2j = 110 11. Bitta tasm a y ordam ida uzatish m um kin b o ‘lgan quvvat. a) N o rm al ponasim on tasm alar uzatm alar uchun [P } = i P 0] ' C a ‘ CL ’ Cu/Cp kVt bunda Ca = 0.95; CL = L J L 0 = 954/17C0 = 0.56 b o i g a n d a CL = 0.89: C v= \ . 12; Cp = 1.1 P0 = 1.39кВт natijada, [P] = 1.39- 0.95 -0.89 ■ 1.12/3.1 = 1.2кВт b) Y arim ponasim on tasm alar uzatm alar uchun l P } = l P b l ’ Ca -CL‘ Cv /Cp kVt bunda: Ca = 0.94; CL = L / I 0= 9 4 4 / 7 1 0 = 1.3 b o i g a n d a CL = 1.04; Cy= 1 .12; Cp = 1.1 (23.2-jadval) PD = 0.29kBi natijada, [P] = 0.29 • 0.94 • 1.04 • 1.12/3.1 = 0.29kBi 148 v) Ensiz ponasim on tasm alar uzatm alar uchun [ P ] - [ P 0 } - c a -c L - c u/ c p kVt bunda: Ca = 0.91; CL = L/L0=518/1600 = 0.32 boTganda CL = 0.91; Cy= 1.12; = 1.1 (23.2-jadval) P0 = 0.95 k B t natijada, {?] = 0.95« 0.91 * 0.91 * 1.12/1.1 = 0.8 k B t 12. T asm alar yoki tasmadagi ariqchalar soni a) N orm al kesimli ponasim on tasmali uzatm alar tasm alar soni 2 = ^ IFol ' Q bunda: Рг uzatilayotgan quvvat; [p0]-buta tasma y ordam ida uzatiladigan quvvat; Q -tasmalar soni, tasmalar o ‘rtasida yuklanishning notekis taqsimlanishini hisobga oluvchi koeffitsiyent Z = = 3,87 = 3.39 yaxlitlab Z = 4 qabul qilamiz 1P»]-Cz 1.2 '0.95 J n n b) Y arim ponasim on tasmalarda ariqchalar soni Z = т-у— = *'8/ ~ = 15.69 yaxlitlab Z = 16 qabul qilamiz IP q J’Q 0.29*0.80 v) Ensiz tasm alar soni Z = 7 - 7 — = 7— = 5.69 vaxlitlab Z = 6 qabul qilamiz |Pt3-C2 0.e-S.85 J I T 13. Shkivlarning eni a) N orm al kesimli ponasimon tasm alar uchun В = { Z - \)t + 2 f = (4-1)3.3 + 2-10 = 30 Z=4, f=10, t=3.3; b) Y arim ponasim on tasmalar uchun В - ( Z - \)t + 2 f = (16-1)1.0 + 2 - 3.5 = 17.0 Z=16, f=3.5, t= l .0; v) Ensiz ponasim on tasm alar uchun B = ( Z - l ) t + 2 f = (6 — 1) - 2.5 + 2 *8 = 28.S Z=6, f=8.0, t=2.5; 14. Tasmali uzatm alarda boshlang‘ich taranglik kuch a) Norm al kesimli ponasim on tasmalar uchun P, С Fc = 7 5 0 j £ T + Z - q v - H, bunda: f, -u za tila y o tg a n quvvat, kVt; Cp, C a-qiymatlari yuqorida berilgan; V —tasm aning tezligi,м /с; Z - t a s m a l a r soni; q - 1 m tasmaning massasi, кг/м; Uzatm a uchun P, = 3.87 kVt; Cp = 1.1; V = 6.7 м/с; Cs = 0.95; Z — 4; 149 q = 0 .1 к г /м . N atijada, 3.87-1.1 F° = 7 5 0 6 7~ 0 9 5 + 4 ' 0 , 1 ' (6‘7)2 = 520H- b) Y arim p o n asim o n tasm alar uchun 3 87 • 1 1 F0 = 75 0 ' + 16 • 0.009 • (6.7)2 = 530H 0 6.7-0.91 v ) E nsiz ponasim on tasm alar uchun 3 87• 11 F0 - 7 5 0 — — — — + 6 • 0.07 • (4.71 )2 - 754H 0 4.71 • G.91 15. V alga t a ’sir qiluvchi k uchlar a) N o rm al kesim li p onasim on tasm ali uzatm ada Fb = 2F0 s i n ( y ) = 2 • 520sin81°30: = 2 - 5 2 0 - 0 . 9 8 9 0 = 1028H b) Y arim p o n asim o n kesim li tasm ali uzatm alar Fb = 2F0 s i n ( y ) = 2 • 530sin81° = 2 « 53C • 0.9877 = 1047H v) E nsiz kesim li p onasim on tasm ali uzatm alar Fb - 2F0 s m ( ap - 2 ■ 7 5 4 3i n 7 5 ° - 2 -7 5 4 - 0 .9 6 5 9 -= 1457H SAVOL VA TO PSH IRIQ LAR 1. P onasim on, y arim p o n sim o n sim o n , ensiz tasm alarn in g tuzilishi. 2. N orm al p onasim on tasm a turlarini bir-biridan farqi. 3. Y arim p o nasim on tasm a turlari v a bir-biridan farqi. 4. E nsiz pon asim o n tasm a turlari va bir-biridan farqi. 5. T asm a turlari qanday tan lan ad i? 6. Y etaklovchi shkiv diametri qanday aniqlanadi? 7. B itta ta sm a y o rd a m id a uzatish m um kin boMgan q u v v at qanday aniq lan ad i? 8. T asm ala r soni q ancha boMishi m um kin? 9. Val tay an c h ig a ta 's ir qiladigan kuch qiym ati qanday aniq lan ad i? Download 5.58 Mb. Do'stlaringiz bilan baham: |
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