Examples for solving problems .
1. The white color of the pumpkin fruit is represented by the dominant W gene, while the yellow color is represented by the Y gene. The W gene is an epistatic gene and does not cause the Y gene effect. Recessive alleles of these genes give a green color in the form of homozygotes.
A. When the two yellow-fruited pumpkins were mixed together, the yellow and green pumpkins were in a 3: I ratio. Identify the genotype of the parent forms.
B. If digeterozygous white-fruited pumpkins are cross- bred, what is the separation at F 1 .
A. Solution
Characters. Genes:
yellow y
white W; WY-:
green wwyy
According to the condition of the matter, in order for a yellow fruit to be formed, the genotype must have a dominant Y gene and a homozygous w gene. Therefore, we obtain the genotype of the mixed forms as follows:
P wwYy x wwYy
Gametes: wY, wy wY, wy
F I wwYY, wwYy, wwYy, wwyy
Thus, 3 parts yellow I part green pumpkins are formed.
B. Solution:
We write the configuration scheme:
P WwYy x WwYy
WY, Wy, wY, wy WY , Wy, wY, wy
By placing gametes in the pannet cells , we create combinations of them.
Table 9
|
WY
|
Wy
|
wY
|
wy
|
WY
|
WWYY
|
WWYy
|
WwYy
|
WwYy
|
Wy
|
WWYy
|
WWyy
|
WwYy
|
Wwyy
|
wY
|
WwYY
|
WwYy
|
wwYY
|
wwYy
|
wy
|
WwYy
|
Wwyy
|
wwYy
|
wwyy
|
Thus, individuals with an epistatic dominant gene W in the genotype appear to be white. The development of pumpkin color in the F 2 generation as a result of the epistatic effect of genes .
We divide the zygotes in the cells into classes.
Genotype: Phenotype:
9-WY- white
3-Wy- white
3-wY- yellow
1-wy- green
Such yellow, but recessive genes will be green pumpkins.
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