Omonov sherozbek

43 – rasm.

3-misol: Yon tomoni 16 sm bo’lgan teng yonli trapetsiya asoslari 10 sm va 34 sm. Shu trapetsiyaning yuzi topilsin (44-rasm).

Yechish: BE=h AD tushiramiz. sm.
ABE dan: BE²=AB²-AE²=256-144=112; h=BE= sm. U holda, S_tp= sm².
B C

AD=34 sm
h AB=16 sm

BC=10 sm
A E F D
44– rasm.

4-misol: Trapetsiyaning diagonallari uning o’tkir burchaklarining bissektrisalari bo’lib, o’rta chiziqni 10 sm va 18 sm ga teng bo’lgan ikki qismga bo’ladi. Trapetsiyaning perimetrini toping.

Yechish: ABCD trapetsiya chizamiz (45-rasm). AC, BD diagonallar va EF o’rta chiziq o’tkazamiz. EH= 10 sm, HF =18 sm bo’lsin, va (shartiga ko’ra). Endi, va (ichki almashinuvchi burchaklar bo’lgani uchun). U holda, ABC va BDC- teng yonli. Ulardan: AB=BC=CD. Ammo, trapetsiyaning o’rta chizig’i dan: sm. ning o’rta chizig’i dan: BC= 20 sm. Demak, sm.
Javob: P=96 sm.
B C




E F
H H₁

A 45 – rasm D

5-misol: ABCD trapetsiyaning kichik asosi 6 ga teng. Agar ning (BE CD) perimetri 36 ga teng bo’lsa, trapetsiyaning perimetrini toping.
Yechish:
B 6 C

A E D
46-rasm.

BC=6, P_ABE=36. P_ABCD=AB+6+BE+AE+6=36+12=48

6-misol: Trapetsiyaning yuzi 594 ga, balandligi 22 ga, asoslari ayirmasi 6 ga teng. Trapetsiyaning katta asosini uzunligini toping.

Y echish:
Y

h
47-rasm

X
H=22,
x=30
7 -misol: Qavariq to’rtburchakning diogonallari uning nechta uchburchakka ajratadi.
Javob: 8 ta




48-rasm

8-misol: Tomonlari 5 sm va 6 sm bo’lgan parallelogrammning yuzi 24 sm² ga teng. Parallelogrammning kichik diogonalini toping.

Yechish:
B C

5

A 6 D