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49-rasm.
S=AB*AD sin =24, 5*6sin =24, sin =4/5 cos =3/5 Kosinuslar teoremasiga ko’ra: BD2=25+36-60cos =61-60*3/5=25 BD=5. 9-misol: Agar rombning tomoni 10 ga, burchaklaridan biri esa 1500ga teng bo’lsa, uning yuzi qanchaga teng bo’ladi? Yechish: S=absin =10*10sin300=100*1/2=50 300 . 1500 50-rasm 10-misol: To’g’ri to’rtburchakning to’g’ri burchagi uchidan uning diogonaliga tushirilgan perpendikulyar to’g’ri burchakni 3:1 kabi nisbatda bo’ladi. Shu perpendikulyar bilan boshqa diogonali orasidagi burchakni toping. Yechish. 4x=900, x=22,50, ADB=90-x=67,50. DBC+ OCB=2 OBC=2*67,50=1350. BOC=1800-(1350)=450 OAA1=450. B C
O
A1 3x x A D 51-rasm. 11-misol: Diogonallari 6 va 8 ga, ular orasidagi burchak 600 ga teng bo’lgan parallelogrammning perimetrini toping. Y echish: B y C x A D
AC=8, BD=6, COD=600 12-misol: Trapetsiyaning asoslari 2 va 3 ga, katta asosiga yopishgan burchaklari 300 va 450 ga teng bo’lsa, trapetsiyaning yuzi qanchaga teng bo’ladi? Yechish: B C h h
53-rasm. BC=2, AD=3, A=300, D=450. 13-misol: ABCD to’g’ri to’rtburchakda AD=12, CD=5, O – diogonallarning kesishish nuqtasi. ni toping. Yechish: B C O
5 A 12 D
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