University of business and science

Tushunganingizni tekshiring
1) 3, 5, 7, ... progreessiyada �(4)a(4)a, left parenthesis, 4, right parenthesis ni toping.
�(4)=a(4)=a, left parenthesis, 4, right parenthesis, equals 

Tekshirish
[Yordam kerak!]
2) Ixtiyoriy �nn had raqami uchun �(�−1)a(n−1)a, left parenthesis, n, minus, 1, right parenthesis nimani ifodalaydi?
Bitta javobni tanlang:
Bitta javobni tanlang:

• 
  (Tanlov A)
  

111 dan �-n-n, start text, negative, end texthadni ayirish
A
111 dan �-n-n, start text, negative, end texthadni ayirish

• 
  (Tanlov B)
  

�-n-n, start text, negative, end texthaddan oldingi had
B
�-n-n, start text, negative, end texthaddan oldingi had
Tekshirish
[Yordam kerak!]
Arifmetik progressiyaning rekursiv formulasi
Rekursiv formula bizga ikkita qism haqida maʼlumot beradi:

1. 
   Progressiyaning birinchi hadi
   
2. 
   Oldingi haddan foydalanib progressiyaning ixtiyoriy hadini topish uchun namuna
   

Quyida 3, 5, 7, ... progressiya uchun rekursiv formula keltirilgan.
{�(1)=3←Birinchi had - uch.�(�)=�(�−1)+2←Oldingi hadga ikkini qoʻshing.⎩⎪⎪⎨⎪⎪⎧​a(1)=3a(n)=a(n−1)+2​←Birinchi had - uch.←Oldingi hadga ikkini qoʻshing.​
Masalan, beshinchi hadni topish uchun biz progressiyani had bo‘yicha kengaytiramiz:

�(�)a(n)a, left parenthesis, n, right parenthesis	=�(� ⁣− ⁣ ⁣1)+2=a(n−1)+2equals, a, left parenthesis, n, minus, 1, right parenthesis, plus, 2
�(1)a(1)a, left parenthesis, 1, right parenthesis			=3=3equals, start color #11accd, 3, end color #11accd
�(2)a(2)a, left parenthesis, 2, right parenthesis	=�(1)+2=a(1)+2equals, a, left parenthesis, 1, right parenthesis, plus, 2	=3+2=3+2equals, start color #11accd, 3, end color #11accd, plus, 2	=5=5equals, start color #aa87ff, 5, end color #aa87ff
�(3)a(3)a, left parenthesis, 3, right parenthesis	=�(2)+2=a(2)+2equals, a, left parenthesis, 2, right parenthesis, plus, 2	=5+2=5+2equals, start color #aa87ff, 5, end color #aa87ff, plus, 2	=7=7equals, start color #1fab54, 7, end color #1fab54
�(4)a(4)a, left parenthesis, 4, right parenthesis	=�(3)+2=a(3)+2equals, a, left parenthesis, 3, right parenthesis, plus, 2	=7+2=7+2equals, start color #1fab54, 7, end color #1fab54, plus, 2	=9=9equals, start color #e07d10, 9, end color #e07d10
�(5)a(5)a, left parenthesis, 5, right parenthesis	=�(4)+2=a(4)+2equals, a, left parenthesis, 4, right parenthesis, plus, 2	=9+2=9+2equals, start color #e07d10, 9, end color #e07d10, plus, 2	=11=11equals, 11

Qoyil! Bu formula bizga 3, 5, 7, ... progressiya kabi progressiyani berdi.