7 -“A”, “B” Algebra
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7 - sinf algebra II - chorak
Misol.
a) (3a – 5bd + bc)(– 2d) . (3a – 5bd + bc)(– 2d) = (3a) (– 2d) + (– 5bd) (– 2d) + (bc)(– 2d) = = – 6ad + 10bd2 – 2bcd . b) (– 6xy)(2x3 + 7x2 –3x+4) . (– 6xy)(2x3 + 7x2 –3x+4) = (– 6xy)(2x3) + (– 6xy)(7x2) + (– 6xy)(–3x)+ +(– 6xy)·4 = – 12x4y – 42 x3y + 18x2y – 24xy . 274 – misol. 1) -5(10 + m) = -50 – 5m 5) 2(3a2 – 4a + 8) = 6a2 – 8a + 16 2) EMBED Equation.3 6) EMBED Equation.3 3) EMBED Equation.3 7) (3a – 5b + bc) (-3) = 9a - 15b – 3bc 4) (-2m + 3n)(-10) = 20 m – 30n 8) (-5)(3x3 + 7x2 –x)= -15x3 – 35x2 +5x Uyga vazifa: 276 – misol. Sana: 14.12. 2016 sinf 7 Algebra Mavzu: Misollar yechish. Darsdan maqsad. a)Ta’limiy:–O’quvchilarga Ko’phadni birhadga ko’paytirish haqida tushunchalar berish b) Tarbiyaviy: - O’quvchilarni vatanparvarlik ruhida tarbiyalash. c) Rivojlantiruvchi: - Mavzuga doir misollar yechish. Dars turi:Savol – javob.. Metodlari: Amaliyot Dasr jihozi: 7 - sinf Algebra o’quv qo’llanmasi Asosiy tushunchalar Ko’phadni birhadga ko’paytirish Bilimlar:- Ko’phadni birhadga ko’paytirishi bilish. Ko’nikmalar:- Ko’phadni birhadga ko’paytirishga doir misollar yecha olish Dars tafsilotlari Tashkiliy qism (3-minut): O’quvchilar bilan salomlashiladi, o’quvchilarning davomati aniqlanadi. Sinf xonanning darsga tayyorligi tekshiriladi. Uyga vazifani tekshirish Har tomonlama bilimlarni tekshirish Yangi bilimni o’zlashtirish 277 – misol. 1) 17a(5a + 6b – 3ab) = 85a2 + 102ab – 51a2b 2) 8ab(2b – 3ac + c2) = 16ab2 – 24a2c + 8abc2 3) 3x2y(5x + 6y + 7z) = 15x3y + 18x2y2 + 21x2yz 4) xyz(x2 + 2y2 + 3z2) = x3yz + 2xy3z + 3xyz3 279 – misol. 1) 6(2t – 3n) – 3(3t – 2n) = 12t – 18n – 9t + 6n = 3t – 12n 2) 5(a - b) – 4(2a – 3b) = 5a – 5b – 8a + 12b = -3a + 7b 3) -2(3x – 2y) – 5(2y – 3x) = - 6x + 4y – 10y + 15x = 9x + 6y 4) 7(4p + 3) - 6(5 + 7p) = 28p + 21 – 30 – 42p = -14p – 9 280 –misol. 1) (x2 - 1)3x – (x2 – 2 ) 2x = 3x3- 3x – 2x3 + 4x = x2 + x 2) (4a2 – 3b)2b – (3a2 – 4b) 3b = 8a2b – 6b2 – 9a2b + 12b2 = -a2b + 6b2 3) 2(3a + 4) +3(a - 7) – 7(2a - 7) = 6a + 8 + 3a – 21 – 14a + 49 = = 6a + 3a – 14a +8 – 21 + 49 = - 5a + 36 4) 3(2x - 1) – 5(x - 3) + 6(3x - 4) = 6x – 3 – 5x + 15 + 18x – 24 = = 6x – 5x + 18x – 3 + 15 – 24 = 19x – 12 Uyga vazifa: 282 – misol. Sana: 16.12. 2016 sinf 7 Algebra Mavzu:Ko’phadni ko’phadga ko’paytirish. Darsdan maqsad. Download 419 Kb. Do'stlaringiz bilan baham: |
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