7 -“A”, “B” Algebra


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7 - sinf algebra II - chorak

Misol.
a) (3a – 5bd + bc)(– 2d) .
(3a – 5bd + bc)(– 2d) = (3a) (– 2d) + (– 5bd) (– 2d) + (bc)(– 2d) =
= – 6ad + 10bd2 – 2bcd .
b) (– 6xy)(2x3 + 7x2 –3x+4) .
(– 6xy)(2x3 + 7x2 –3x+4) = (– 6xy)(2x3) + (– 6xy)(7x2) + (– 6xy)(–3x)+ +(– 6xy)·4 = – 12x4y – 42 x3y + 18x2y – 24xy .


274 – misol.
1) -5(10 + m) = -50 – 5m 5) 2(3a2 – 4a + 8) = 6a2 – 8a + 16
2) EMBED Equation.3 6) EMBED Equation.3
3) EMBED Equation.3 7) (3a – 5b + bc) (-3) = 9a - 15b – 3bc
4) (-2m + 3n)(-10) = 20 m – 30n 8) (-5)(3x3 + 7x2 –x)= -15x3 – 35x2 +5x

Uyga vazifa: 276 – misol.
Sana: 14.12. 2016 sinf 7 Algebra
Mavzu: Misollar yechish.
Darsdan maqsad.
a)Ta’limiy:–O’quvchilarga Ko’phadni birhadga ko’paytirish haqida tushunchalar berish
b) Tarbiyaviy: - O’quvchilarni vatanparvarlik ruhida tarbiyalash.
c) Rivojlantiruvchi: - Mavzuga doir misollar yechish.
Dars turi:Savol – javob..
Metodlari: Amaliyot
Dasr jihozi: 7 - sinf Algebra o’quv qo’llanmasi
Asosiy tushunchalar
Ko’phadni birhadga ko’paytirish
Bilimlar:- Ko’phadni birhadga ko’paytirishi bilish.
Ko’nikmalar:- Ko’phadni birhadga ko’paytirishga doir misollar yecha olish
Dars tafsilotlari
Tashkiliy qism (3-minut): O’quvchilar bilan salomlashiladi, o’quvchilarning davomati aniqlanadi. Sinf xonanning darsga tayyorligi tekshiriladi.
Uyga vazifani tekshirish
Har tomonlama bilimlarni tekshirish
Yangi bilimni o’zlashtirish
277 – misol.
1) 17a(5a + 6b – 3ab) = 85a2 + 102ab – 51a2b
2) 8ab(2b – 3ac + c2) = 16ab2 – 24a2c + 8abc2
3) 3x2y(5x + 6y + 7z) = 15x3y + 18x2y2 + 21x2yz
4) xyz(x2 + 2y2 + 3z2) = x3yz + 2xy3z + 3xyz3


279 – misol.
1) 6(2t – 3n) – 3(3t – 2n) = 12t – 18n – 9t + 6n = 3t – 12n
2) 5(a - b) – 4(2a – 3b) = 5a – 5b – 8a + 12b = -3a + 7b
3) -2(3x – 2y) – 5(2y – 3x) = - 6x + 4y – 10y + 15x = 9x + 6y
4) 7(4p + 3) - 6(5 + 7p) = 28p + 21 – 30 – 42p = -14p – 9


280 –misol.
1) (x2 - 1)3x – (x2 – 2 ) 2x = 3x3- 3x – 2x3 + 4x = x2 + x
2) (4a2 – 3b)2b – (3a2 – 4b) 3b = 8a2b – 6b2 – 9a2b + 12b2 = -a2b + 6b2
3) 2(3a + 4) +3(a - 7) – 7(2a - 7) = 6a + 8 + 3a – 21 – 14a + 49 =
= 6a + 3a – 14a +8 – 21 + 49 = - 5a + 36
4) 3(2x - 1) – 5(x - 3) + 6(3x - 4) = 6x – 3 – 5x + 15 + 18x – 24 =
= 6x – 5x + 18x – 3 + 15 – 24 = 19x – 12
Uyga vazifa: 282 – misol.
Sana: 16.12. 2016 sinf 7 Algebra
Mavzu:Ko’phadni ko’phadga ko’paytirish.
Darsdan maqsad.

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