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Sample Problems.
1.
Suppose that P1,000 is borrowed at a simple interest rate of 18% per annum. At the end of one
year, the interest would be:
I = (P) (n) (i)
I = 1,000 (1) (0.18) = P 180
2.
Michelle invested $5000.00 in mutual fund with the interest rate of 4.8%.
How much interest
would she earn after 2 years?
P = $5000.00 ; i= 4.8% ; n= 2
I = (P) (n) (i)
I = ($5000.00)(4.8%)(2) = $480.00
Hence, Michelle would earn $480 after 2 years.
3.
Jeff has one savings account with the interest rate of 3.3%, and one money market account with
the interest rate of 5.1% in a bank. If he deposits $1,200.00
to the savings account, and
$1,800.00 to the money market account, how much money will he have after 6 years?
Savings account:
P = $1,200.00
i = 3.3%
n= 6
Money market account:
P = $1,800.00
i = 5.1%
n = 6
I = ($1,200.00) (3.3%) (6)]
I = 237.60
= ($1,800.00)[1+(5.1%)(6)]
= ($1,800.00)(1.306)
= $2,350.80
F = P + I
F = $1,200.00 + 237.60
F = $1,437.60
Total amount:
$1437.60 + $2350.80
= $3,788.40
Hence, Jeff will have $3,788.40 after 6 years.
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