Ikki noma`lumli tenglamalar


-misol. sistemani grafik usulda yeching. Yechish


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5-misol. sistemani grafik usulda yeching.
Yechish: x+y=2 to`g`ri chiziqni va x2+y2=22 aylanani bitta chizma-da chizamiz va ularning kesishish nuqtalari A (2;0) va B (0; 2) ni topa-miz. Sistemaning yechimi (2; 0) va (0; 2) bo`ladi (12-rasm).




12-rasm.


Mashqlar

Quyidagi sistemalarni qulay usul bilan yeching:


153. 1) 2)


154. 1) 2)


155. 1) 2)


156. 1) 2)


157. 1) 2)


158. 1) 2)


159. 1) 2)


160. 1) 2)


161. 1) 2)


162. 1) 2)


Javoblar:

153. 2) ; 154. 2) (6; 35); 155. 2) (4; 1); 156. 2) (5; 1);


157. 2) (7; -5); (-4; 6); 158. 2) , (-2; 1); 159. 2) (2; 3), (3, 2);


60. 2) (1; 3), (3, 1); 161. 2) (1; 3), (3; 1); 162. 2) (3; 2), (-3; -2), , .




7.4. Ikkinchi va uchinchi tartibli determinantlar


son ikkinchi tartibli determinant deyiladi. son uchinchi tartibli deter-minant deyiladi (hisoblash qoidasi o`ng tomonida tuzilgan hadlar tuzilishi qoidasidan iborat).


Misol. .



7.5. Chiziqli tenglamalar sistemasini
Kramer usulida yechish


sistema berilgan bo`lsa, uning yechimi bo`ladi, bu yerda


Misol. sistemani yeching.






Javob. .


sistemaning yechimi bo`lib,



Keltirilgan usul chiziqli tenglamalar sistemasini Kramer usulida yechish deyiladi.





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